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Alona [7]
3 years ago
15

A solution is prepared by adding 100 ml of 0.2 m hydrochloric acid to 100 ml of 0.4 m sodium formate. is this a buffer solution,

and if so, what is its ph?
Chemistry
1 answer:
bogdanovich [222]3 years ago
6 0
<span>It is a buffer because pH = pKa of formic acid. </span>
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I WILL MAKE U THE BRAINLIEST !!
bogdanovich [222]

Answer:

Try using Ptable or chemicalaid

Explanation:

Ptable is a great website that shows you a dynamic periodic table. It can show you which elements are Halogens, Alkali metals, transition metals, noble gases, and etc!

Chemicalaid is a nice website to find out more information about specific elements, it also lists every element on the periodic table.

5 0
3 years ago
H2o has how many atoms in it? 1,2, or 3?
liraira [26]
H2o only has two atoms in it.
(just trying to make this text longer,,,)
4 0
3 years ago
Definition of the word derived?
FromTheMoon [43]

Answer:

obtain something from (a specified source).

Explanation:

6 0
4 years ago
Read 2 more answers
Type the correct answer in the box. express your answer to three significant figures. an air mattress is filled with 0.55 moles
dmitriy555 [2]

385 L is the volume of the air mattress with 0.55 moles of air inside the mattress and a temperature of 295 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.5 kPa

V=?

n= 0.55 moles of air

T= 295K

R= 8.314 (L kPa/mol K)

Putting value in the given equation:

V= \frac{nRT}{P}  

V = \frac{(0.55 moles)(8.314 L kPa/mol k)(295 K)}{3.5 kPa}

V = 385.4132857 L

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 litres.

Hence, 385.4132857 L is the volume of the air mattress.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

5 0
2 years ago
Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?
Step2247 [10]
Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

                               C     +     O2      ------>  CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2. 

                          <u>     86.5 g CO       </u>   = 1.966 moles CO2
                            44 g CO2/ mole

Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel. 

        1.966 moles CO2   x   <u>   1 mole C   </u>    x   <u>   </u><u>12 g C   </u>  = 23.59 g C
                                             1 mole CO2          1 mole C

We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams. 


            25.0 g - 23.59 g = 1.41 grams Hydrogen 

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen. 

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel, 

Carbon:     <u>  1.966 mol   </u>   = 1.408   x   5 (factor)     = 7
                    1.396 mol

Hydrogen:  <u>  1.396 mol   </u>    = 1.00   x    5 (factor)    = 5
                     1.396 mol

Thus, the empirical formula is C7H5

       
4 0
4 years ago
Read 2 more answers
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