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zheka24 [161]
3 years ago
12

How is impure copper refined by electrolysis

Chemistry
1 answer:
Gelneren [198K]3 years ago
6 0

Answer:

By giving electricity to copper compound solution.

Explanation:

Electrolysis is one of the major way of refined copper. The copper containing solution has two electrodes.i) positive electrodes called anode. ii) negative electrodes called cathode. When electricity is pass into the copper containing solution electrolysis process is starts and impure copper is formed in anode and pure copper is formed in cathode.

So, We can get pure copper in cathode through electrolysis.

I Hope this will be helpful for you.

If this is helpful for you .Then choose this answer as brainliest answer.

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elena55 [62]
I believe the answer is filtration.
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Fill in the coefficients that will balance the following reaction: a0NaCl + a1FeO → a2Na2O + a3FeCl2
Helen [10]

Answer:

2NaCl + FeO —-> 2Na2O + FeCl2

Explanation:

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Which element is likely to be the best conductor of electricity?
Eddi Din [679]

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3 years ago
How many moles are in 3.113 g of Au?Molar mass of Au=197 g/mol
SVEN [57.7K]
<h3>Answer:</h3>

0.0157 g Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.113 g Au

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 197.87 g/mol

<u>Step 3: Convert</u>

<u />3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} ) = 0.015733 g Au

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.015733 g Au ≈ 0.0157 g Au

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3 years ago
What's the purpose of mitosis and meiosis?
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