Answer:
A scientist who studies water and its properties is a hydrologist.
Explanation:
A hydrologist is a scientist linked to the study of water, both surface and underground, detecting cleanliness or contamination and proposing alternatives for its cleaning and conservation.
A hydrologist's research on the properties of water, its location, distribution and circulation contributes to the maintenance of the environment.
The other options are not correct because:
<em> A) </em><u><em>Entomologist
</em></u><em>: a scientist who studies insects.</em>
<em> B) </em><u><em>Chemist
</em></u><em>: a professional who studies the elements and chemical compounds and their properties.</em>
<em> D) </em><u><em>Oceanographer</em></u><em>
: study both oceans and seas, and their relationship with the environment, the atmosphere and the land.</em>
<em> E) </em><u><em>Toxicologist</em></u><em>: study the effects of toxic or harmful substances on living beings and the environment.</em>
The epidermal tissue would form a boundary between the plant and it's environment so it probably wouldn't prevent asexual reproduction. Predation doesn't making sense because it's a plant, not an animal prey. Water loss is the best answer because the thick boundary prevents some water from evaporating.
Answer:D) 5-carbon compound
Explanation: During the light independent reactions, the first step in the cycle is carbon dioxide fixation in which three molecules of carbon dioxide is fixed into three molecules of a 5- carbon compound known as ribulose 1, 5- bisphosphate in a reaction catalyzed by ribulose 1, 5 -bisphosphate carboxylase (rubisco)
Answer:
The result will be two gametes with a normal haploid number (n), one gamete containing an extra chromosome (n + 1) and one gamete missing one chromosome (n − 1).
Explanation:
Nondisjunction is caused by the failure in the mechanism of separation of homologous chromosomes or sister chromatids during meiosis and/or mitosis. The failure in the separation of sister chromatids during meiosis II is referred to as 'secondary nondisjunction' and it produces two daughter cells with abnormal chromosome numbers.
The fusion of one gamete containing an extra chromosome (n + 1) with a normal (n) gamete will lead to trisomy (2n + 1), while the fusion of one gamete missing one chromosome (n - 1) with a normal gamete will lead to monosomy (2n-1).
The answer is C.) The volume of fluid in Image B is greater than that of Image A.
