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3 years ago

Anyone who understand this for 16 point s plz

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

5 0

This is pretty open-ended. How about:

$\sqrt 2$ and $\sqrt 3$ are similar because they're both irrational, meaning neither is the ratio of two integers.

$\sqrt 2$ and $\sqrt 3$ are different because $\sqrt{2} < 1.5}$ and $\sqrt{3} > 1.5$ .

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Answer:

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4 years ago

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Jason has a bar of chocolate he gives his friend 2/5 of his chocolate bar.what percentage of his bar of chocolate does he have l

ddd [48]

Answer:

60%

Step-by-step explanation:

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3 years ago

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Explain why the solution of 5x – 3 > 14.5 or 2x+5/3 < 4 has a solution of all real numbers, with one exception.

AlexFokin [52]

Answer: The solution of given inequalities is all real number except [1.167, 3.5].

Explanation:

The given inequalities are

$5x-3>14.5$ ....(1)

$2x+\frac{5}{3}$ .... (2)

Solve first inequality.

$5x-3>14.5$

$5x>14.5+3$

$x>\frac{17.5}{5}$

$x>3.5$

Solve second inequality.

$2x+\frac{5}{3}$

$2x$

$x$

The solution of first or second inequality is all real number less than 1.167 and all rea number more than 3.5. It means the combined solution of both inequalities is all real number except [1.167, 3.5].

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3 years ago

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In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist

Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

$np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96$

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

$\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408$

#Define Y:

Y~(11.04,5.7408)

$P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291$

Hence, the probability of 12 or fewer is 0.8291

b. The probability that 5 or more fish were caught.

#Using normal approximation:

$P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968$

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above $P(X\geq 5)=0.9968$ and a , $P(X\leq 12)$ =0.7291

$P(5\leq X\leq 120\approx P(4.5\leq Y\leq 12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259$

Hence, the probability of between 5 and 12 is 0.7259

4 0

3 years ago

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

Sholpan [36]

Answer:

6x − y = 1 -------(1)

4x − 3y = −11 ------(2)

(1)×3

18x - 3y =3 ------(3)

4x − 3y = −11 ------(2)

(3)+(2)

18x - 3y + ( 4x - 3y) = 3+(-11)

d. 4x − 3(−6x − 1) = −11 is the answer.

8 0

3 years ago