Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
I need the values of either X or Y to solve this. I can solve for what X is though.
Step-by-step explanation:
A: X = -12
B: X =78
C: X = 12.13
I hope this helps you, but since both X and Y are unknown variables, you can't solve it, only simplify (which it already is.)
Step-by-step explanation:
quisiera ayudarte pero no hablo inglés :(
Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Answer:
B ( 432 units^2)
Step-by-step explanation:
Total surface area= 2*(6*6)+ 4*(15*6)
There are 2 squares at each end of the same size so total area will be 2*(6*6)
If we look at the rectangles( bottom, top and the sides), we can see that all are of same dimensions and there are 4 of them so it's 4*(15*6)
In short, total surface area= 2*(6*6)+ 4*(15*6) = 432 units^2