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3 years ago

Can classical physics be used to accurately describe a satellite moving at a speed of 7500 m/s? explain why or why not.

1 answer:

3 0

The classical physics works on the Newton's laws of motion. It is applicable on heavenly bodies which are governed by the gravitational force. On the other hand, Quantum Physics is applicable for very low mass and sized bodies like electron, protons etc. The classical physics would accurately describe the motion of satellite moving with speed 7500 m/s using the following formula:

$r=\frac {GM}{v^{2}}$

where G is the gravitational constant, M is the mass of the planet and v is the orbital speed. Then radius of the orbit can be described by this formula.

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TEA [102]

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. ... In reaction, a thrusting force is produced in the opposite direction.

Explanation:

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2 years ago

A force exerted on an object produces acceleration. If the mass remains the same and the acceleration is doubled, the force must

Inga [223]

<h2>Answer</h2>

The force will be doubled.

<h2>Explanation</h2>

Using Newton Law II,

So it can be seen in the formula that force is directly proportional to mass and acceleration.

if mass is doubled ---> force will be doubled, keeping acceleration constant.

Similarly,

if acceleration is doubled ---? force is will be doubled, keeping mass constant.

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2 years ago

A 54 kg pig runs at a speed of 1.0

olchik [2.2K]

Answer:

27 Joules.

Explanation:

use the formula for kinetic energy:

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3 years ago

An engine does 10 J of work and exhausts 25 J of waste heat during each cycle.

noname [10]

The thermal efficiency is defined as follows

$\eta = 1 - \frac{Q_{\text{out}}}{Q_\text{in}}$ ,

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In your case $Q_\text{in} = 25 \text{ J},W_\text{out}=10 \text{ J}.$

So $Q_\text{out}=10 \text{ J}$ which gives an efficiency of

$\eta = 1 - \frac{10 \text{ J}}{25 \text { J}} = 0.6 = 60 \%$ .

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3 years ago