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Delvig [45]
3 years ago
11

Can classical physics be used to accurately describe a satellite moving at a speed of 7500 m/s? explain why or why not.

Physics
1 answer:
gogolik [260]3 years ago
3 0

The classical physics works on the Newton's laws of motion. It is applicable on heavenly bodies which are governed by the gravitational force. On the other hand, Quantum Physics is applicable for very low mass and sized bodies like electron, protons etc. The classical physics would accurately describe the motion of satellite moving with speed 7500 m/s using the following formula:

r=\frac {GM}{v^{2}}

where G is the gravitational constant, M is the mass of the planet and v is the orbital speed. Then radius of the orbit can be described by this formula.

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A scientist uses a camera to study the stars.
Mars2501 [29]

Answer:

It would most likely be 3!

Explanation:

A scientist taking photos of the stars would be using those photos as a sort of documentation. The only reason to record this is for data or research purposes, meaning that 1 and 2 are incorrect. While 4 is a possibility, it is a fruitless endeavor, as even if you managed to count all the stars in the night sky at one point, it would completely discount every star not visible from that part of the globe, making the data false/pointless. Again, this is just my educated assumption, but I do think the answer is 3. Good luck :D

4 0
3 years ago
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The word gymnosperm comes from two Greek words: gymno, meaning bare, and sperm, meaning_____ . Unlike other seed plants, gymnosp
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Explanation:

8 0
3 years ago
Two objects (42.0 and 21.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
Kazeer [188]

Answer:

a = 3.27 m/s²

T = 275 N

Explanation:

Given that:

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The acceleration can be determined as:

(m_1+m_2)a = g(m_1-m_2)

Making acceleration the subject in the above formula;

a =\dfrac{g(m_1-m_2)}{(m_1+m_2)}

a =\dfrac{9.8(42.0-21.0)}{(42.0+21.0)}

a =\dfrac{9.8(21.0)}{(63.0)}

a =\dfrac{205.8}{(63.0)}

a = 3.27 m/s²

in the string, the tension is calculated using the formula:

T = \dfrac{2m_1m_2g}{(m_1+m_2)}

T = \dfrac{2(42)(21)(9.81)}{(42+21)}

T = \dfrac{17304.84}{63}

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T ≅ 275 N

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2 years ago
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3 years ago
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I hope that this was helpful for you.
7 0
3 years ago
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