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OlgaM077 [116]
3 years ago
14

A 5.00 kilogram mass is traveling at 100. meters per second. Determine the speed of the mass after an impulse with a magnitude o

f 30.0 newton • seconds is applied.
Physics
2 answers:
faltersainse [42]3 years ago
5 0

m = mass = 5 kg

v_{i} = initial velocity = 100 m/s

v_{f} = final velocity = ?

I = impulse = 30 Ns

Using the impulse-change in momentum equation

I = m(v_{f} - v_{i})

30 = 5 (v_{f} - 100)

v_{f} = 106 m/s

Romashka [77]3 years ago
5 0
The answer to this question is <span>106 m/s</span>
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Answer:

During the section CD , the speed is fastest.

Explanation:

The rate of change of distance is called speed.

Speed = distance / time

Its SI unit ism/s. It is a scalar quantity.

The slope of the distance time graph is given by the speed of the object.

Here, the speed of AB is 30/3= 10 m/s .

The speed of BC is = 0 m/s

The speed of CD is (50 - 30)/(6 - 5) = 20 m/s

So, the speed is maximum during the section CD.

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6 seconds is the best answer

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Which of the following factors will negatively impact the rate of diffusion of a molecule?
Maurinko [17]

Answer:

A low difference in the concentration of the molecule across the media

Explanation:

Diffusion is a type of passive transport where the molecules move in the influence of concentration gradient of diffusing molecules i.e. from the higher concentration region to the lower concentration region. There are some factors which affect the rate of diffusion, these are written below -

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2200000 = 2.2E6 min for light from Proxima to reach earth

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