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Mrrafil [7]
2 years ago
8

When a person falls from certain height on cemented floor, he receives more injuries why​

Physics
1 answer:
monitta2 years ago
8 0

Explanation:

When a man falls on a hard cemented floor his momentum reduced to zero in a very short time and hurt the man. Whereas when a man falls on a heap of sand. As sand can compress, it takes longer time for the man to hit the ground (or hard surface)

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PLEASE ANSWER 50 POINTS SPENT I'LL GIVE BRAINLIEST TO THE PERSON WHO ANSWERS ALL! (or most)
Afina-wow [57]

Answer:

1) The matter absorbs or reflects the light

2) Lens

3) <u><em>Concave</em></u>- curves inwards.  Diverges light

b.<u><em>Convex</em></u>- curves outward.  Converges light

4) The image is real if the distance of the object from the lens is greater than the focal length and virtual if it is less than the focal length

5) Lens and, for convex lenses, on the distance between the lens and the object.

6) Index of refraction?

Explanation:

I hope this helped you, sorry if anything is wrong

6 0
3 years ago
A glass lying on table doesn't possess friction.why?
Ratling [72]
Becsud it's not moving
7 0
3 years ago
The resistance between 2 points in an electrical circuit is 1.1 Ω. What additional resistance
valentinak56 [21]

Answer:

the new resister is 11 ohms.

Explanation:

Set it  up like this.

1/x + 1/1.1 = 1                    Subtract 1/1.1 from both sides

1/x = 1 - 1/1.1

1 - 1/1.1 = 1/11

1/x = 1/11                          Cross multiply

11 = x

If 1/11 bothers you, you could do it it another way.

1 - 1/1.1 = (1.1 - 1 ) / 1.1 = 0.1 / 1.1  Multiply top and bottom by 10

0.1*10/(1.1 * 10 ) = 1 / 11

5 0
2 years ago
Question 15 of 25
stira [4]
Combustion reaction
5 0
2 years ago
A metal can containing condensed mushroom soup has mass 215 g, height 10.8 cm, and diameter 6.38 cm. It is placed at rest on its
s344n2d4d5 [400]

Answer:

Part a)

Moment of inertia of the cylinder is given as

I = 1.21 \times 10^{-4} kg m^2

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as I = 1/2 mR^2

Explanation:

As we know that the inclined plane is of length L = 3 m

and its inclination is given as 25 degree

so we know that acceleration of center of mass of the cylinder is constant so we will have

v_f^2 = v_i^2 + 2 a L

so we have

v_f^2 = 0 + 2a(3)

now we know that

v_{avg} = \frac{L}{t} = \frac{v_f + v_i}{2}

\frac{3}{1.50} = \frac{v_f + 0}{2}

v_f = 4 m/s

Now we have know that final speed of the cylinder due to pure rolling is given as

v_f = \sqrt{\frac{2gH}{1 + \frac{I}{mR^2}}}

4 = \sqrt{\frac{2(9.81)(3 sin25)}{1 + \frac{I}{0.215(0.0319)^2}}}

I = 1.21 \times 10^[-4} kg m^2

Part B)

Height of the cylinder is of no use here to calculate the inertia

Part C)

Since we don't know about the viscosity data of the soup inside the cylinder so we can't say directly about the moment of inertia of the cylinder as I = 1/2 mR^2

8 0
3 years ago
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