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xxTIMURxx [149]
3 years ago
6

select the three objectives mosquitoes hovered around the small puddle of still murky water in the background ​

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0

Answer:

Step-by-step explanation:

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3 years ago
How would you classify the number 121 ?<br>​
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Answer:

\boxed{121\:  is \:  a \: perfect \: square}

Step-by-step explanation:

the \:  \sqrt[3]{121}  \: is \: not \: a \: perfect \: cube \\ but \\ the \:  \sqrt{121}  = 11 \to \: is \: a \: perfect \: square \\

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3 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
FIND THE SURFACE AREA. I WILL MARK YOU A BRAINLEST IF THE ANSWER IS RIGHT
garik1379 [7]

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4 0
3 years ago
Read 2 more answers
Who is farthest from the school
postnew [5]

Using the law of cosines:

The grocery store to the school:

Distance = √(7^2 + 10^2 - 2*7*10*cos(100)

Distance = 13.16 miles


The movie store to the school:

Distance = √(7^2 + 10^2 - 2*7*10*cos(120)

Distance = 14.80 miles


The friend is further away.

7 0
3 years ago
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