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3 years ago

Through any three non collinear points there exists exactly

1 answer:

7 0

Through any three noncollinear points there exists exactly one plane. Hope this is the answer you are looking for! Any questions about my answer then feel free to ask in the comments below!!!

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PLEASE HELP EASY MATH!

Ahat [919]

X=3 ex:3-8=-5 and -5x4=-20 -20+14=-6

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3 years ago

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aniked [119]

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3 years ago

Which set is a function?

sergiy2304 [10]

The correct answer is B. A function is defined as a set of values or points in which each x value is only paired with one value. All the other choices have x values that repeat but no x values in choice B repeat.

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3 years ago

Read 2 more answers

A number y is 3 times greater than a number x. Which equation shows this relationship

vladimir1956 [14]

Answer:

y = 3x

Step-by-step explanation:

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6 0

3 years ago

I need help! (HAPPY MLK DAY!!!)

olga2289 [7]

The slope and length of the given sides of the quadrilateral can be

found by using the coordinates of the vertices.

Correct responses:

$Slope \ of \ \overline{IJ} = \underline{-\dfrac{7}{6} }$ , Length of $\overline{IJ}$ = $\underline{\sqrt{85} }$

$Slope \ of \ \overline{JK} = \underline {-\dfrac{2}{9}}$ , Length of $\overline{JK}$ = $\underline{\sqrt{85} }$

$Slope \ of \ \overline{KL} = \underline{-\dfrac{7}{6} }$ , Length of $\overline{KL}$ = $\underline{\sqrt{85}}$

$Slope \ of \ \overline{LI} = \underline{ -\dfrac{2}{9} }$ , Length of $\overline{LI}$ = $\underline{\sqrt{85} }$

<h3>Methods used to find the slope and length of a line</h3>

The given coordinates of the vertices are;

K(-7, 0), J(2, -2), I(8, -9), L(-1, -7)

$Slope = \mathbf{\dfrac{y_2 - y_1}{x_2 - x_1}}$

$Length \ of \ line = \mathbf{ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}$

Therefore;

$Slope \ of \ \mathbf{\overline{IJ}} = \dfrac{-2 - (-9)}{2 - 8} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}$

$Length \ of \ \mathbf{\overline{IJ}} = \sqrt{(2 - 8)^2 + (-2 - (-9))^2} = \underline{\sqrt{85}}$

$Slope \ of \ \mathbf{\overline{JK}} = \dfrac{0 - (-2)}{-7 - 2} = \dfrac{2}{-9} = \underline{-\dfrac{2}{9}}$

$Length \ of \ \mathbf{\overline{JK}} = \sqrt{(-7 - 2)^2 + (0 - (-2))^2} = \underline{ \sqrt{85}}$

$Slope \ of \ \mathbf{\overline{KL}} = \dfrac{0 - (-7)}{-7 - (-1)} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}$

$Length \ of \ \mathbf{\overline{KL} }= \sqrt{(-7 - (-1))^2 + (0 - (-7))^2} =\underline{ \sqrt{85}}$

$Slope \ of \ \mathbf{\overline{LI}} = \dfrac{(-9 - (-7))}{(8 - (-1))} = \dfrac{-2}{9} = \underline{-\dfrac{2}{9}}$

$Length \ of \ \mathbf{\overline{LI}} = \sqrt{(8 - (-1))^2 + (-9 - (-7))^2} = \underline{\sqrt{85}}$

Learn more about finding the slope and length of a line here:

brainly.com/question/11612395

brainly.com/question/14039630

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3 years ago