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3 years ago

Which of the following is an arithmetic sequence?

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

Answer:

B is an arithmetic sequence because the number that you add or subtract between each number has to match

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What is 1/4 multiplied by 3 as a mixed number

Colt1911 [192]

Answer:

3/4

Step-by-step explanation:

1/4 * 3 = 3/4

This is a fraction, not a mixed number

7 0

3 years ago

Suppose h is a function such that h(2) = −3, h'(2) = 3, h''(2) = 4, h(5) = 5, h'(5) = 6, h''(5) = 12, and h'' is continuous ever

elena55 [62]

Answer:

Step-by-step explanation:

It seems like your question is not complete.

So I will asume that it is like the one in the image.

But probably the answer is not 3 if the range is different from (1-2), eventhough, you just have to follow the same steps.

6 0

4 years ago

Fewer young people are driving. In year A, 67.9% of people under 20 years old who were eligible had a driver's license. Twenty y

aleksley [76]

Answer:

Case a Case b

margin of error 0.0216 0.0231

Interval estimate (0.7016 , 0.6795) (0.5031 , 0.4569)

margin of error is not same in both cases.

Step-by-step explanation:

At 95% confidence interval the interval estimate of number of 20 year old drivers in year A can be computed as

p' ± z $\sqrt{\frac{p'(1-p')}{n} }$

= 0.68 ± 1.96 $\sqrt{\frac{0.68(1-0.68)}{1800} }$

= 0.7016 , 0.6795

the margin of error can be written as

z $\sqrt{\frac{p'(1-p')}{n} }$

= 1.96 $\sqrt{\frac{0.68(1-0.68)}{1800} }$

= 0.0216

At 95% confidence interval the interval estimate of number of 20 year old drivers in year B can be computed as

p' ± z $\sqrt{\frac{p'(1-p')}{n} }$

= 0.48 ± 1.96 $\sqrt{\frac{0.48(1-0.48)}{1800} }$

= 0.5031 , 0.4569

the margin of error can be written as

z $\sqrt{\frac{p'(1-p')}{n} }$

= 1.96 $\sqrt{\frac{0.48(1-0.48)}{1800} }$

= 0.0231

Sample size is same in case A and B but proportion is different in both cases so margin of error is different in both cases

3 0

3 years ago

The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π).

Effectus [21]

Answer:

$\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}$

Step-by-step explanation:

Given the quadratic equation as:

$2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0$

Let us put $sinx=y$ for simplicity of the equation:

Now, the equation becomes:

$2y^2+y-1=0$

Now, let us try to solve the quadratic equation:

$\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1$

So, the solution to the given trigonometric quadratic equation is:

$sinx = \dfrac{1}{2}$

and

$sinx=-1$

Let us try to find the values of $x$ in the interval $[0, 2\pi)$ .

$sin\theta$ can have a value equal to $\frac{1}{2}$ in 1st and 2nd quadrant.

So, $x$ can be

$30^\circ, 150^\circ\\OR\\\dfrac{\pi}{6}, \dfrac{5\pi}{6}$

For $sinx=-1$ ,

$x = 270^\circ\ or\ \dfrac{3 \pi}{2}$

So, the answer is:

$\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}$

7 0

3 years ago

Algebra I WILL GIVE BRAINLIEST

docker41 [41]

Answer:

23/7 times 23/7

Step-by-step explanation:

5 0

3 years ago