Question

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Answer 1

Answer:

OPTION - 3: -m²n³$\sqrt{n}$

Step-by-step explanation:

We know that $\sqrt{ab} = \sqrt{a}\sqrt{{b}$

Also, $\sqrt{m^{2}} = m$

Now we are to simplify: $- \sqrt{m^4n^7}$

$\implies - \sqrt{m^4}\sqrt{n^7}$

$\implies - \sqrt{(m^2)^2}\sqrt{n^6.n}$

$\implies- m^2 \sqrt{(n^3)^2.n}$

$\implies - m^2 n^3\sqrt{n}$

∴                       $\sqrt{m^4n^7} = -m^2n^3\sqrt{n}$