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3 years ago

Complete the square to transform the quadratic equation into the form (x – p)2 = q.

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

5 0

X^2 - 6x - 8 = 6
x^2 - 6x = 14
(x - 3)^2 - 9 = 14
(x - 3)^2 = 23

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Writing unit fractions to add or subtract.

Ivahew [28]

1/3 + 1/6

---Find a common denominator, or the least common multiple of the given denominators. In this case, that would be 6.

1/3 = 2/6

1/6 = 1/6

---Now add the fractions

2/6 + 1/6

3/6

---Simplify/Reduce the fraction

3/6

1/2

Answer: 1/2

1/3 + 1/6 = 2/6 + 1/6 = 3/6 (or 1/2)

Hope this helps!

3 0

2 years ago

Read 2 more answers

Jessica hit a golf ball 150.75 yards. Kayla hit a golf ball 130.25 yards. How much farther did Jessica hit a golf ball?

Lapatulllka [165]

Answer:

Jessica hit the golf ball 20.50 yards farther than Kayla.

Step-by-step explanation:

150.75 - 130.25 = 20.50 yards

If this answer is correct, please make me Brainliest!

6 0

3 years ago

Read 2 more answers

What transformation is shown below?

Artist 52 [7]

Answer:

it's a translation

Step-by-step explanation:

it just moved (3,0). If it were a rotation the y-axis wouldn't be the same. If it were a reflection you would be able to flip the blue triangle onto the red triangle.

6 0

3 years ago

you make a salary of $700 per week. you have an insurance deduction of $65 per week and 12% withheld for taxes after your deduct

fgiga [73]

$700 - 65 = 635 \times .12 = 76.2$
$635 - 76.2 = 558.8$
$558.8 \times 12 = 6705.6$

8 0

3 years ago

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a

Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = $\sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}$

= ${^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}$ + .......+ ${^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}$

= 0.04541 + ......+0.0000002079

= 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0

3 years ago