Answer:
The equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:
Step-by-step explanation:
The slope-intercept form of the line equation
where
Given the line
3x - 4y = 7
writing in the slope-intercept form
4y = 3x - 7
dividing both sides by 4
4y/4 = 3/4x - 7/4
y = 3/4x - 7/4
Now, comparing with the slope-intercept form of the line equation
y = 3/4x - 7/4
The slope of the line m = 3/4
We know that parallel lines have the same slopes.
Therefore, the slope of the parallel line is: 3/4
now we have,
The point (-4, -2)
The slope m of parallel line = 3/4
Given the point-slope form of the line equation
where m is the slope of the line and (x₁, y₁) is the point
substituting (-4, -2) and m = 3/4 in the point-slope form of line equation
![\:y-\left(-2\right)=\frac{3}{4}\left(x-\left(-4\right)\right)](https://tex.z-dn.net/?f=%5C%3Ay-%5Cleft%28-2%5Cright%29%3D%5Cfrac%7B3%7D%7B4%7D%5Cleft%28x-%5Cleft%28-4%5Cright%29%5Cright%29)
![y+2=\frac{3}{4}\left(x+4\right)](https://tex.z-dn.net/?f=y%2B2%3D%5Cfrac%7B3%7D%7B4%7D%5Cleft%28x%2B4%5Cright%29)
Thus, the equation in the point-slope form of the line equation is:
![y+2=\frac{3}{4}\left(x+4\right)](https://tex.z-dn.net/?f=y%2B2%3D%5Cfrac%7B3%7D%7B4%7D%5Cleft%28x%2B4%5Cright%29)
Simplifying the equation
![y+2=\frac{3}{4}\left(x+4\right)](https://tex.z-dn.net/?f=y%2B2%3D%5Cfrac%7B3%7D%7B4%7D%5Cleft%28x%2B4%5Cright%29)
Subtract 3 from both sides
![y+2-2=\frac{3}{4}\left(x+4\right)-2](https://tex.z-dn.net/?f=y%2B2-2%3D%5Cfrac%7B3%7D%7B4%7D%5Cleft%28x%2B4%5Cright%29-2)
![y=\frac{3}{4}x+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B4%7Dx%2B1)
Multiplying the equation by 4
![4y = 3x + 4](https://tex.z-dn.net/?f=4y%20%3D%203x%20%2B%204)
![3x - 4y = -4](https://tex.z-dn.net/?f=3x%20-%204y%20%3D%20-4)
Therefore, the equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:
Answer:
likely, impossible, unlikely
Step-by-step explanation:
Answer:
first answer is correct
Step-by-step explanation:
Hello, we want to write 2 + 4 + 6 + ... + 20
for n = 1, 2n = 2*1 =2
for n = 2, 2n = 2*2=4
for n = 3, 2n=2*3=6
etc
so
![\displaystyle \sum_{n=1}^{10} {2n} = 2*1 + 2*2 +2*3+2*4+...+2*10=2+4+6+8+...+20](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bn%3D1%7D%5E%7B10%7D%20%7B2n%7D%20%3D%202%2A1%20%2B%202%2A2%20%2B2%2A3%2B2%2A4%2B...%2B2%2A10%3D2%2B4%2B6%2B8%2B...%2B20)
thanks
There is 1 gram is a milliliter and grams to milligrams is 16,000
so 16,000 is your answer
<span>Let C represent the total cost (in dollars),
and let S represent the amount of sugar (in tons) transported
equation:
C(s) = </span><span>225s + 7500
</span><span>find the total cost to transport 11 tons of sugar.
</span>C(11) = 225(11) + 7500
C(11) = 2475 + 7500
C(11) = 9975
hope it helps