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Svetllana [295]

3 years ago

12

Belts at a department store cost &12 each. Use items from the tiles to complete the proportional relationship of total cost(

$),c, for a number of belts,b

1 answer:

Gnesinka [82]3 years ago

3 0

Answer:

C=12b

..........

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olga_2 [115]

Hey! I’m not sure what you’re needing help on but if it’s an answer i’m pretty sure the answer would be - 180 (hx)

5 0

1 year ago

By selling a bag at RS 1500 and RS 2100, there is some profit respectively. if the loss is twice the profit, find its cost price

Doss [256]

may be this helpfulness!

6 0

3 years ago

What is the domain

xenn [34]

<h3>Answer: Give the domain and the range of each quadratic function whose graph is described. The vertex is (−1,−2)(−1,−2) and the parabola opens up.</h3>

8 0

2 years ago

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Use the power property to rewrite log3x^9

GalinKa [24]

For properties of logarithm we have the following:

loga (x ^ b) = b * loga (x)

Therefore, following this property we have for this case:

log3 (x ^ 9) = 9log3 (x)

Answer:

the power property to rewrite log3x9 is:

9log3x

8 0

3 years ago

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<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =

Georgia [21]

Answer: $\dfrac{1}{2\sqrt x}$

<u>Step-by-step explanation:</u>

$\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}$

f(x) = $\sqrt x\\$

f(x+h) = $\sqrt{x+h}$

$\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}$

$=\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)$

$=\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{1}{\sqrt{x+h}+\sqrt x}$

$=\dfrac{1}{\sqrt{x+0}+\sqrt x}$

$=\dfrac{1}{2\sqrt x}$

4 0

3 years ago