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Elanso [62]
3 years ago
6

Someone help plz make sure it’s right if it is will mark brainiest:)

Mathematics
1 answer:
timurjin [86]3 years ago
8 0

Answer:

39

Step-by-step explanation:

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Joe what's to build a fence for his dog Charlie he plans to surround the rectangle to the right with fence. How many feet will h
Aleksandr [31]
Joe wants to build a fence for his dog Charlie.
The lengths of the perimeter of the rectangle that he plans to surround with fence are as follows:

10 feet + 15 feet + 10 feet + 15 +feet.

The total perimeter area of a rectangle is worked out as follows:
10 + 15 + 10 + 15 = 50 
Therefore Joe needs 50 feet of fencing to totally surround the rectangle with fence. 
3 0
4 years ago
At a school, 4 out of every 7
luda_lava [24]

Answer:

60 girls play sports

Step-by-step explanation:

#1- divide 105 by 7=15

#2- multiply 4 by 5= 60

therefore 60 of the 105 girls play sports

5 0
3 years ago
Read 2 more answers
–4(3 – 5x)≥ –6x + 9?
ollegr [7]

Answer:

x \geqslant  \frac{21}{26}

Step-by-step explanation:

divide both sides by 26 and then simplify

4 0
3 years ago
Need help with this problem its really complicated for me
ddd [48]

You can write a proportion because the two triangles are similar

\frac{x}{x-2} = \frac{x + x + 5}{x + 1 + x - 2} (the second fraction is longer because I added the full lengths of the larger triangle)  cross multiply to get (x)(x + 1 + x - 2) = (x - 2)(x + x + 5)

which simplifies to (x)(2x - 1) = (x - 2)(2x + 5)

then 2x² - x = 2x² + 5x -4x - 10

then 2x² - x = 2x² + x - 10

then 2x² = 2x² + 2x - 10

subtract 2x² from both sides to get 0 = 2x - 10

add 10 to both sides to get 10 = 2x

divide both sides by 2 to get 5 = x

8 0
3 years ago
Look at this triangle<br>B<br>11 cm<br>4 cm<br>A4<br>C<br>Work out length AC.pythagoras<br><br>​
german

Answer:

11.7 cm

Step-by-step explanation:

Using Pythagoras Theorem

AC² = AB² + BC²

AB = 4 cm

BC = 11 cm

AC² = 4² + 11²

AC = √4² + 11²

AC =✓137

AC = 11.704699911 cm

Approximately = 11.7 cm

Length AC = 11.7cm

6 0
3 years ago
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