Answer:
![\left[\begin{array}{ccc}-30&22&8\\-4&-4&16\\30&-28&18\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-30%2622%268%5C%5C-4%26-4%2616%5C%5C30%26-28%2618%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given
![A = \left[\begin{array}{ccc}-1&9&2\\10&-10&2\\-5&6&-5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%269%262%5C%5C10%26-10%262%5C%5C-5%266%26-5%5Cend%7Barray%7D%5Cright%5D)
![B = \left[\begin{array}{ccc}7&-1&-1\\6&-4&-3\\-10&10&-7\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-1%26-1%5C%5C6%26-4%26-3%5C%5C-10%2610%26-7%5Cend%7Barray%7D%5Cright%5D)
Required
2A - 4B
To solve 2A - 4B, we first multiply matrix A by 2 and matrix B by 4
So, if
![A = \left[\begin{array}{ccc}-1&9&2\\10&-10&2\\-5&6&-5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%269%262%5C%5C10%26-10%262%5C%5C-5%266%26-5%5Cend%7Barray%7D%5Cright%5D)
![2A = 2 *\left[\begin{array}{ccc}-1&9&2\\10&-10&2\\-5&6&-5\end{array}\right]](https://tex.z-dn.net/?f=2A%20%3D%202%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%269%262%5C%5C10%26-10%262%5C%5C-5%266%26-5%5Cend%7Barray%7D%5Cright%5D)
![2A = \left[\begin{array}{ccc}-2&18&4\\20&-20&4\\-10&12&-10\end{array}\right]](https://tex.z-dn.net/?f=2A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%2618%264%5C%5C20%26-20%264%5C%5C-10%2612%26-10%5Cend%7Barray%7D%5Cright%5D)
If
![B = \left[\begin{array}{ccc}7&-1&-1\\6&-4&-3\\-10&10&-7\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-1%26-1%5C%5C6%26-4%26-3%5C%5C-10%2610%26-7%5Cend%7Barray%7D%5Cright%5D)
then
![4B = 4*\left[\begin{array}{ccc}7&-1&-1\\6&-4&-3\\-10&10&-7\end{array}\right]](https://tex.z-dn.net/?f=4B%20%3D%204%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-1%26-1%5C%5C6%26-4%26-3%5C%5C-10%2610%26-7%5Cend%7Barray%7D%5Cright%5D)
![4B = \left[\begin{array}{ccc}28&-4&-4\\24&-16&-12\\-40&40&-28\end{array}\right]](https://tex.z-dn.net/?f=4B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%26-4%26-4%5C%5C24%26-16%26-12%5C%5C-40%2640%26-28%5Cend%7Barray%7D%5Cright%5D)
So; 2A - 4B becomes
![\left[\begin{array}{ccc}-2&18&4\\20&-20&4\\-10&12&-10\end{array}\right] - \left[\begin{array}{ccc}28&-4&-4\\24&-16&-12\\-40&40&-28\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%2618%264%5C%5C20%26-20%264%5C%5C-10%2612%26-10%5Cend%7Barray%7D%5Cright%5D%20-%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%26-4%26-4%5C%5C24%26-16%26-12%5C%5C-40%2640%26-28%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}-2-28&18-(-4)&4-(-4)\\20-24&-20-(-16)&4-(-12)\\-10-(-40)&12-40&-10-(-28)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2-28%2618-%28-4%29%264-%28-4%29%5C%5C20-24%26-20-%28-16%29%264-%28-12%29%5C%5C-10-%28-40%29%2612-40%26-10-%28-28%29%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}-30&18+4&4+4\\20-24&-20+16&4+12\\-10+40&12-40&-10+28\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-30%2618%2B4%264%2B4%5C%5C20-24%26-20%2B16%264%2B12%5C%5C-10%2B40%2612-40%26-10%2B28%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}-30&22&8\\-4&-4&16\\30&-28&18\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-30%2622%268%5C%5C-4%26-4%2616%5C%5C30%26-28%2618%5Cend%7Barray%7D%5Cright%5D)
Hence, 2A - 4B is equivalent to
![\left[\begin{array}{ccc}-30&22&8\\-4&-4&16\\30&-28&18\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-30%2622%268%5C%5C-4%26-4%2616%5C%5C30%26-28%2618%5Cend%7Barray%7D%5Cright%5D)
The answer to your question is h < 10.3
Because if you add 9 to both sides (1.3+9) you'll get h <10.3
hope this helps. Peace out homie
Answer:
-16+12= -4
Step-by-step explanation:
When we mins 12 from 16 (16-12) we get 4.
Similarly. When we minus 16 from 12 (12-16) we get -4 because we choose the sign with the greater number.
I'd start by writing an equation for each of the right triangles. (Pythagorean theorem)
y² + 9² = z²
x² + z² = (4+9)²
4² + y² = x²
we want to find z so combine the equations by substituting the other variables x,y out.
substitute y² for (x² - 4²) in 1st equation.
(x² - 4²) + 9² = z²
now by rearranging the 2nd equation we can substitute x² for (13² - z²)
(13² - z²) - 4² + 9² = z²
169 - z² - 16 + 81 = z²
234 - z² = z²
234 = 2z²
234/2 = z²
117 = z²
√(117) = z
√(9*13) = z
3√(13) = z
13 goes in the box
Answer:
First, convert the hour to minutes.
1 hr = 60 mins
15 mins: 60 mins
1:4