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Setler [38]
3 years ago
15

Find the area and perimeter of the rectangle whose sides are lengths 2x + 3 and 4x.

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0

The answer to this problem is 3(2x+1)

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I will give brainliest to the best answer.
aniked [119]

Given that two digit numbers are used and one digit is drawn randomly.

Sample space = {10,11,...99}

n(S) = 90

32 is only one number favorable

Hence P(32) = 1/90

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Odd numbers are exactly 45.

Hence prob (odd number) = 45/90 = 1/2

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Multiples of 5 are 10,15,.....95

There are exactly 18 numbers.

Hence P(a multiple of 5) = 18/90 =1/5

Have an amazing day! <3

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What is 2878 divided by 55
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Read 2 more answers
A given rectangle has an area of 20 ft.² what is the length for various widths
ruslelena [56]
The area of a rectangle is calculated as length times its width. So, for the given area above, the expression should b written as:

20 = LW

To know the length for various measurement of the width, we can write it by:

L = 20 / W

You can substitute any measurement to W and you can obtain the corresponding value of the length.
8 0
3 years ago
Evaluate the expression for x = 5, y = 3, and z = 14 . 5x−6y+20z over 4yz Enter your answer in the box.
spin [16.1K]

Hello from  MrBillDoesMath!


Answer:   1 17/24


Steps:

          Evaluate             (5x-6y+20x)/ 4yz when x = 5, y = 3, z = 14


          (5(5) - 6(3) + 20(14))   / 4 (3)(14)          (Substitute in values)

       = (25   - 18    +280)       / 4 (3) (14)         (Evaluate products)

       =  (287) /  4 (3) (14)                                (Evaluate expressions)

      =  287/ 168                                             (4 (3)(14) = 168)

      =  (168  + 119 ) /168                                 287 = 168  + 119

      = (168)/168 + 119/168

      = 1              + 119/168

      = 1  119/168          

       BUT 119 = 17 * 7  (surprise!)  and 168 = 12 * 7 * 2 so answer

    =  1 (17*7)/(12*7*2)

    =  1 (17)/(12*2)                               (Cancel 7's)

    = 1 (17/24)                                    


Regards, MrB    


3 0
3 years ago
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