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3 years ago

If wavelength increases, frequency would ______?

Physics

2 answers:

Leya [2.2K]3 years ago

7 0

Answer:

decreases

Explanation:

When frequency

increases more wave crests pass a fixed point each second. That means

the wavelength shortens. So, as frequency increases, wavelength

decreases. The opposite is also true—as frequency decreases,

wavelength increases.

IrinaVladis [17]3 years ago

6 0

Answer:

increase with it

Explanation:

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4) A racing car undergoing constant acceleration covers 140 m in 3.6 s. (a) If it’s moving at 53 m/s at the end of this interval

Scorpion4ik [409]

Answer

given,

distance = 140 m

time, t = 3.6 s

moving speed = 53 m/s

a) distance = (average velocity) x time

$D = \dfrac{v_0 + v_1}{2}\times t$

$140 = \dfrac{v_0 + 53}{2}\times 3.6$

v₀ + 53 = 77.78

v₀ = 24.78 m/s or 25 m/s

b) $a = \dfrac{v-u}{t}$

$a = \dfrac{53-25}{3.6}$

a = 7.8 m/s²

using equation of motion

v₀² = v₁² + 2 a s

53² = 0²+ 2 x 7.8 x s

s = 180 m

3 0

3 years ago

According to Lenz's law, an induced current in the direction depicted in the picture would be created when: a. An external downw

LenKa [72]

Answer:

C. An external downward field is created or an external downward field is removed

Explanation:

As we can see that from the attached figure that the induced current would be counter clockwise. So the field occur because of induced current i.e. out of page. This represent that the current is induced in order to rise the flux out of the direction of the page

Therefore because of the external field, the field out of page & flux would be reducing or the external upward field is eliminated

So option C is correct

7 0

3 years ago

Name TWO WEAKNESSES of the model pictured below

Nikolay [14]

Answer:

Here are a few:

1) The orbital radius of these planets is ridiculously small an in no way representative of their actual radii.

2) The planets will only line up like that once every 5200 years, making this very unrepresentative of their usual relations - although this does make their order in distance from the sun.

3) The nebulae, comet, lens flare, and other junk in the background is incorrect.

4) If this is meant as a representation of the planets, then Pluto should not be there as it is now considered a planetoid.

5) The planets are incorrectly scaled both to each other and to the sun.

7 0

3 years ago

Captain John Stapp is often referred to as the "fastest man on Earth." In the late 1940s and early 1950s, Stapp ran the U.S. Air

valentina_108 [34]

Answer:

The sled needed a distance of 92.22 m and a time of 1.40 s to stop.

Explanation:

The relationship between velocities and time is described by this equation: $v_f=v_0+a*t$ , where $v_f$ is the final velocity, $v_0$ is the initial velocity, $a$ the acceleration, and $t$ is the time during such acceleration is applied.

Solving the equation for the time, and applying to the case: $t=\frac{v_f-v_0}{a}=\frac{0\frac{m}{s}-282\frac{m}{s} }{-201\frac{m}{s^2} }=1.40s$ , where $v_f=0\frac{m}{s}$ because the sled is totally stopped, $v_0=282\frac{m}{s}$ is the velocity of the sled before braking and, $a=-201\frac{m}{s^2}$ is negative because the deceleration applied by the brakes.

In the other hand, the equation that describes the distance in term of velocities and acceleration: $x_f-x_0=v_0*t+\frac{1}{2}*a*t^2$ , where $x_f-x_0$ is the distance traveled, $v_0$ is the initial velocity, $t$ the time of the process and, $a$ is the acceleration of the process.