All categories

3 years ago

PLS HELP :) GIVING BRAINLIEST SIMPLE SCIENCE QUESTION HELPS PLSSSS

Physics

1 answer:

raketka [301]3 years ago

3 0

OMG ITS B ITS B I HOPE I HELPED U

You might be interested in

For segment r and segment l to hold together, they must exert forces on each other. what is the direction of the force exerted o

Inga [223]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The <span> direction of the force exerted on segment r by segment l is left.

</span>The forces on segment R are
1. the force due to L and
<span>2. the pull (to the right) at the right end of the rope.</span>

4 0

3 years ago

2. An object goes from a speed of 9 m/s to a total stop (Om/s) in 3 s. What

xxMikexx [17]

Acceleration = (0-9) / 3 = -3m/s^2

5 0

3 years ago

How fast, in meters per second, does an observer need to approach a stationary sound source in order to observe a 1.6 % increase

morpeh [17]

Answer:

The value is $v_o = 5.488 \ m/s$

Explanation:

From the question we are told that

The emitted frequency increased by $\Delta f = 1.6 \% = 0.016 \$

Let assume that the initial value of the emitted frequency is

$f = 100\% = 1$

Hence new frequency will be $f_n = 1 + 0.016 = 1.016$

Generally from Doppler shift equation we have that

$f_1 = [\frac{ v \pm v_o}{v \pm + v_s } ] f$

Here v is the speed of sound with value $v = 343 \ m/s$

$v_s$ is the velocity of the sound source which is $v_s = 0 \ m/s$ because it started from rest

$v_o$ is the observer velocity So

Generally given that the observer id moving towards the source, the Doppler frequency becomes

$f_1 = [\frac{ v + v_o}{v + 0 } ] f$

=> $1.016 = [\frac{ 343 + v_o}{343 } ] * 1$

=> $v_o = 5.488 \ m/s$

8 0

3 years ago

A car starts from rest and accelerates uniformly over a time of 7 seconds for a distance of 190m. Find the the acceleration of t

Mama L [17]

Answer:

a = 7.75 [m/²]

Explanation:

To solve this problem we must use the following equation of kinematics.

$x=x_{0} +v_{o} *t + (\frac{1}{2})*a*t^{2}$

where:

x = final distance = 190 [m]

Xo = initial distance = 0

Vo = initial velocity = 0 (car starts from the rest)

a = acceleration [m/s²]

t = time = 7 [s]

190 = 0 + (0*7) + 0.5*a*(7²)

190 = 0.5*49*a

a = 7.75 [m/²]

4 0

3 years ago

What is the role of the ocular lens?

konstantin123 [22]

It's a type of lens that is attached to a variety of optical devices such as telescopes and microscopes. It is so named because it is usually the lens that is closest to the eye when someone looks through the device.

3 0

3 years ago