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Keith_Richards [23]
3 years ago
11

What term describes matter that is a substance made of different kinds of atoms bonded together?

Chemistry
2 answers:
Natasha_Volkova [10]3 years ago
7 0

Answer:

The actual answer is compounds from the science notebook

Explanation:

Afina-wow [57]3 years ago
5 0
Compounds or molecules
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Titanium has an HCP unit cell for which the ratio of the lattice parameters c/a is 1.58. If the radius of the Ti atom is 0.1445
Karolina [17]

The unit cell volume of the crystal is V_c = 9.9084*10^-^2^3 cm^3 / unit cell and the density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Data;

  • radius = 0.1445 nm
  • c/a = 1.58
  • A = 46.88 g/mol

<h3>Unit Cell Volume</h3>

The unit cell volume can be calculated as

V_c = 6R^2c\sqrt{3}\\

let's substitute the values into the formula

V_c = 6 * (1.445*10^-^8)^2 * 1.58 8 * a * \sqrt{3} \\a = 2R\\V_c = 6 * (1.445*10^-^8)^2 * 1.58* 2 * 1.445*10^-^8 * \sqrt{3}\\ V_c = 9.984*10^-^2^3 cm^3 / unit cell

The unit cell volume of the crystal is V_c = 9.9084*10^-^2^3 cm^3 / unit cell

<h3>Density of Ti</h3>

The density of titanium can be calculated as

\rho = \frac{nA}{V_c N_a}

  • n = 6 for hcp
  • A = 46.88 g/mol
  • Na = Avogadro's number

let's substitute the values into the formula

\rho = \frac{nA}{V_c Na}\\ \rho = \frac{6*46.88}{9.9084*10^-^2^3* 6.023*10^2^3} \\\rho = 4.71 g/cm^3

The density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Learn more on crystal lattice here;

brainly.com/question/6610542

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2 years ago
The electron configuration for aluminum (Al) is shown below:
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It is the third choice

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What is the amount of moles for 12.0 g Ar?
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if i am correct it shall be 12. because i am thinking, 1 mole = 1 ar.

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Using mathematical expressions drive the compression factor​
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just look it up yourself

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