Answer:
graphite
Explanation:
Graphite is opaque, a very good lubricant, a good conductor of electricity, and a thermal insulator. Allotropes of carbon are not limited to diamond and graphite, but also include buckyballs (fullerenes), amorphous carbon, glassy carbon, carbon nanofoam, nanotubes, and others.
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Answer:
- Rubidium Rb was discovered in 1861
- It was discovered by the German chemist Robert Wilhelm Bunsen and the German physicist Gustav-Robert Kirchoff
Explanation:
Rubidium was discovered by the German chemists Robert Bunsen and Gustav Kirchhoff in 1861 while analyzing samples of the mineral lepidolite with a device called a spectroscope. The sample produced a set of deep red spectral lines they had never seen before. Bunsen was eventually able to isolate samples of rubidium metal. Today, most rubidium is obtained as a byproduct of refining lithium.
Answer:
Molarityof the solution is 0.1375 M.
Explanation:
We will first find the number of moles of diethyl ether (C4H10O) by finding its molar mass and measured mass.
Molar mass of diethyl ether (C4H10O) = 74.12 g.
Now, volume of diethyl ether (C4H10O) = 1.15 mL and its density = 0.7134 g/mL.
Therefore, measured mass of diethyl ether (C4H10O) = volume x density = 1.15 mL x 0.7134 g/mL = 0.82 g.
Now, number of moles of diethyl ether (C4H10O) = 
= 0.011 Moles.
Volume of the solution = volume of diethyl ether + volume of dichloromethane = 1.15 mL + 78.85 mL = 80 mL.
Now, molarity of the solution = Number of moles of diethyl ether / Volume of the solution( in mL) x 1000 = 
Heterogenous mixtures can separates due to differences in size of components
Answer:
10.80
Explanation:
As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen reacts with 1 mol of hydrogen.
In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.
We can set up the ratio;
28.01 g of
l
N
2
needs
6.048 g of
l
H
2
1 g of
l
N
2
needs
6.048
28.01
g of
l
H
2
50.0 g of
l
N
2
needs
6.048
×
50.0
28.01
l
g of
l
H
2
=
10.80 g of
l
H
2
