Answer:
d. supersaturated.
Explanation:
A solution naturally contains a solute and a solvent. The solute is the solid substance that dissolves in the solvent, which is usually a liquid substance. A solution has a maximum amount of solute that can dissolve in its constituent solvent.
However, when the amount of dissolved solute in a solution at a given temperature is greater than the amount that can permanently remain in the solution at that temperature, the solution is said to be SUPERSATURATED. This means that the solution contains more than the maximum amount of solute.
Answer:
Bromine gains an electron
Explanation:
According to oxidation and reduction
Aretes and horns
Explanation:
Aretes and horns are the landforms that are created where cirques meet. These landforms are products of glacier erosion in most temperate and polar regions.
- Cirques are common products of alpine glacier erosion.
- They arise in form of bowl shaped hollows on the side of a mountain.
- These hollows joins to form a U-shaped valley called Aretes and unique pointed arcs known as horns.
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Answer:
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
Explanation:
Step 1: Data given
Kp = 4.7 x 10^3 at 400K
Pressure of CH3OH = 0.250 atm
Pressure of HCl = 0.600 atm
Volume = 10.00 L
Step 2: The balanced equation
CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)
Step 3: The initial pressure
p(CH3OH) = 0.250atm
p(HCl) = 0.600 atm
p(CH3Cl)= 0 atm
p(H2O) = 0 atm
Step 3: Calculate the pressure at the equilibrium
p(CH3OH) = 0.250 - X atm
p(HCl) = 0.600 - X atm
p(CH3Cl)= X atm
p(H2O) = X atm
Step 4: Calculate Kp
Kp = (pHO * pCH3Cl) / (pCH3* pHCl)
4.7 * 10³ = X² /(0.250-X)(0.600-X)
X = 0.249962
p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm
p(HCl) = 0.600 - 0.249962 = 0.350038 atm
p(CH3Cl)= 0.249962 atm
p(H2O) = 0.249962 atm
Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)
Kp = 4.7 *10³
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
Answer:
C) C4H6 - Right answer
Explanation:
Let's combine the Ideal Gases Law with density to get the molecular formula for the unknown gas.
Density = mass / volume
1.06 g /L means that 1.06 grams of compound occupy 1 liter of volume.
P . V = n . R . T
Pressure in Torr must be converted to atm
760 Torr are 1 atm
371 Torr are __ (371 .1)/760 = 0.488 atm
0.488 atm . 1L = 1.06g/MM . 0.082 . 304K
(0.488 atm . 1L) / 0.082 . 304K = 1.06g/ MM
Mass / Molar mass = Moles → That's why the 1.06 g / MM
0.0195 mol = 1.06g / MM
1.06g/0.0195 mol = MM → 54.3 g/m
Now, let's use the composition
100 g of compound have 88.8 g of C
54.3 g of compound have ___ (54.3 . 88.8) /100 = 48 g of C
100 g of compound have 11.2 g of H
54.3 g of compound have __ (54.3 . 11.2)/100 = 6 g of H
48 g of C are included un 4 atoms
6 g of H are included in 6 atoms