Next the strontium hydroxide solution prepared in part (a) is used to titrate a nitric acid solution of unknown concentration.Wr
1 answer:
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Answer : The percent yield of is, 68.4 %
Solution : Given,
Mass of = 0.16 g
Mass of = 0.84 g
Molar mass of = 16 g/mole
Molar mass of = 32 g/mole
Molar mass of = 44 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.026 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 2 mole of react to give 1 mole of
So, 0.026 moles of react to give
moles of
Now we have to calculate the mass of
Theoretical yield of = 0.572 g
Experimental yield of = 0.391 g
Now we have to calculate the percent yield of
Therefore, the percent yield of is, 68.4 %
Answer:
See explanation and image attached
Explanation:
When an alkene is reacted with cold, dilute and alkaline KMnO4, the product of the reaction is a 1,2-diol (vicinal diol). The products exhibit a “syn” stereochemistry with the addition of the two -OH groups to the same side of the alkene.
The reaction of cyclopentene with cold, dilute, alkaline KMnO4 is shown in the image attached.
