Answer:
Sr(OH)₂(aq) + 2 HNO₃(aq) ⇒ Sr(NO₃)₂(aq) + 2 H₂O(l)
Explanation:
Let's consider the unbalanced molecular equation between strontium hydroxide and nitric acid solutions. This is a neutralization reaction, since an acid reacts with a base to form a salt and water.
Sr(OH)₂(aq) + HNO₃(aq) ⇒ Sr(NO₃)₂(aq) + H₂O(l)
We have 2 N atoms on the right side, so we have to multiply HNO₃ by 2.
Sr(OH)₂(aq) + 2 HNO₃(aq) ⇒ Sr(NO₃)₂(aq) + H₂O(l)
Finally, to get the balanced equation we will multiply H₂O by 2.
Sr(OH)₂(aq) + 2 HNO₃(aq) ⇒ Sr(NO₃)₂(aq) + 2 H₂O(l)