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Irina-Kira [14]
3 years ago
7

Next the strontium hydroxide solution prepared in part (a) is used to titrate a nitric acid solution of unknown concentration.Wr

ite a balanced chemical equation to represent the reaction between strontium hydroxide and nitric acid solutions.
Chemistry
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

Sr(OH)₂(aq) + 2 HNO₃(aq) ⇒ Sr(NO₃)₂(aq) + 2 H₂O(l)

Explanation:

Let's consider the unbalanced molecular equation between strontium hydroxide and nitric acid solutions. This is a neutralization reaction, since an acid reacts with a base to form a salt and water.

Sr(OH)₂(aq) + HNO₃(aq) ⇒ Sr(NO₃)₂(aq) + H₂O(l)

We have 2 N atoms on the right side, so we have to multiply HNO₃ by 2.

Sr(OH)₂(aq) + 2 HNO₃(aq) ⇒ Sr(NO₃)₂(aq) + H₂O(l)

Finally, to get the balanced equation we will multiply H₂O by 2.

Sr(OH)₂(aq) + 2 HNO₃(aq) ⇒ Sr(NO₃)₂(aq) + 2 H₂O(l)

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The value of Kc for the thermal decomposition of H₂S is 2.2 x 10⁻⁴ at 1400 K:
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initial                  3.5 M               0           0
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6 0
3 years ago
Chemistry check please... Thank you!
I am Lyosha [343]
1) We apply the ideal gas equation:
PV = nRT
n = (21300 x 3/1000) / (8.314 x 323)
n = 0.024
Your answer is correct.

2) Total pressure = Partial pressure of Hydrogen + Partial pressure of water
134.7  = 122.4 + Pw
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Your answer is correct

3) The molar fraction, volume fraction and pressure fraction of gasses are the same thing.
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3 0
3 years ago
What is the molarity of a solution composed of 5.85 g of potassium iodide, KI, dissolved
Troyanec [42]

Answer:

0.282 M

General Formulas and Concepts:

<u>Chemistry - Solutions</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Molarity = moles of solute / liters of solution

Explanation:

<u>Step 1: Define</u>

5.85 g KI

0.125 L

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of I - 126.90 g/mol

Molar Mass of KI - 39.10 + 126.90 = 166 g/mol

<u>Step 3: Convert</u>

<u />5.85 \ g \ KI(\frac{1 \ mol \ KI}{166 \ g \ KI} ) = 0.035241 mol KI

<u>Step 4: Find Molarity</u>

M = 0.035241 mol KI / 0.125 L

M = 0.281928

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.281928 M ≈ 0.282 M

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