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3 years ago

How tall is a tree which is 15 feet shorter than a pole that is 3 times as tall as the tree?

Mathematics

1 answer:

Citrus2011 [14]3 years ago

7 0

<h2>Height of tree is 7.5 feet</h2>

Step-by-step explanation:

Let t be the height of pole.

Given that the tree is 5 feet shorter than a pole.

Height of pole = t + 15

Also given that the pole is 3 times as tall as the tree.

Height of pole = 3t

So we have

t + 15 = 3t

2t = 15

t = 7.5 feet

Height of tree = 7.5 feet

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-10x-15y=-30 find y<br><br>show work please

Effectus [21]

-10x - 15y = -30

-10x + 30 = 15y

(30 - 10x) / 15 = y

(30/15) - (10x/15) = y

2 - 2x/3 = y

Answer: y = -2x/3 + 2 or y = 2- 2x/3

5 0

2 years ago

How to solve the area of a triangle

drek231 [11]

<h2>The area A of a triangle is given by the formula A=1/2*b*h where b is the base and h is the height of the triangle.</h2>

Step-by-step explanation:

<h2>The photo which is in the attachment is an example for your question. </h2>

<h2>hope this answer helps you!!</h2>

7 0

2 years ago

Which is a good comparison of the estimated sum and the actual sum of 7 9/12 + 2 11/12?

natta225 [31]

7 9/12 = 7.75
2 11/12 = 2.917

So we can round both of these up.

7.75 rounds to 8
2.917 rounds to 3

8 + 3 = 11

So the estimated sum is 11.

7 9/12 + 2 11/12 = 10 2/3

So the actual sum is 10 2/3.

The estimated sum is a pretty good estimate to the original number.

8 0

2 years ago

Read 2 more answers

What is the following quotient?

mamaluj [8]

Answer:

A. $2(3^{\frac{1}{3}})-\sqrt[3]{18}$

Step-by-step explanation:

We are given that

$\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})$

We have to find the quotient.

$\frac{6}{\sqrt[3]{9}}-3(\frac{\sqrt[3]{6}}{\sqrt[3]{9}})$

$\frac{2\times 3}{\sqrt[3]{3^2}}-3(\frac{\sqrt[3]{3\times 2}}{\sqrt[3]{3^2}})$

$2\times\frac{3}{3^{\frac{2}{3}}}-3(\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3^{\frac{2}{3}}})$

Using the property

$(ab)^n=a^n\cdot b^n$

$2\times 3^{1-\frac{2}{3}}-3(2^{\frac{1}{3}}\times 3^{\frac{1}{3}-\frac{2}{3}})$

Using the property

$\frac{a^x}{a^y}=a^{x-y}$

$2(3^{\frac{1}{3}})-3(2^{\frac{1}{3}}\times 3^{-\frac{1}{3}})$

$2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{1-\frac{1}{3}}$

$2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{\frac{2}{3}}$

$2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{3^2}$

$2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{9}$

$2(3^{\frac{1}{3}})-\sqrt[3]{2\times 9}$

$2(3^{\frac{1}{3}})-\sqrt[3]{18}$

Hence, the quotient of $\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})$ is given by

$2(3^{\frac{1}{3}})-\sqrt[3]{18}$

Option A is correct.

4 0

2 years ago

Read 2 more answers

PLEASE HELP! WILL GIVE BRAINLIEST

Kaylis [27]

Answer:

1. $37.70 of interest

2. Jeans Junction

Step-by-step explanation:

1. For simple interest, we use the equation $A=P(1+rt)$ where

P is the principle or starting value
A is the total amount after interest and a period of time
r is the rate at which interest gathers as a decimal
t the time in years.

For this problem, we know P=$580, r=6.5%=0.065, t=1 year. We substitute into the formula and simplify to find the total amount A.

$A=P(1+rt)\\A=580(1+0.065(1))\\A=580(1+0.065)\\A=580(1.065)\\A=617.70\\$

Using this total amount we can subtract the original principle to find the amount of interest.

617.7-580=$37.70 of interest

2. Jeans Plus sells jeans for $25 a pair At regular price, if I bought 3 I would spend 3j=s(25)=$75 and then received $10 off. SO I would spend $65 total.

Jeans Junction also sells jeans for $25 and will give me 15% off. This means I would pay 85% or 0.85 of the price (100-15=85). So if I buy 3, I would spend 3j=3(250=75. Then I can multiply 75(0.85)=63.75. This is the better deal because I spend less.

6 0

3 years ago