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Black_prince [1.1K]

3 years ago

11

Question 5

1 answer:

Tcecarenko [31]3 years ago

8 0

Answer:

The COP is 0.5

Step-by-step explanation:

First we must find the slopes.

12.50/25 = 0.5

17.50/35 = 0.5

The COP is 0.5

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Which geometric shape can be described as a fixed distance along a line?

saul85 [17]

Hey there!

A fixed distance along a line without any 2nd dimension is a line segment. The reason why it's a line <em>segment</em> instead of a line is that lines go on forever in both directions while a line segment stops at some point on both ends. This is what the problems means when it says "fixed distance".

Hope this helped you out! :-)

3 0

3 years ago

malfutka [58]

Answer:

Answer is option b and c and d

$on \: dividing \: the \: number \: \frac{ - 8}{15} \: we \: get \\ - 0.533333333........ \\ which \: is \: equivalent \: to \: - 0.53$

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

3 0

2 years ago

A certain stock starts the day at $273/8 per share. If it drops $21/2 during the day, what is its closing value? A. $247/8 B. $2

Elza [17]

Answer:

A. $ 24 7/8

Step-by-step explanation:

GIVEN: A stock starts the day at $27 3/8 per share.

Share drops $2 1/2 during the day.

To Find : Closing value

Solution : first we need to find how many 1/8 are there in 1/2

So, $\frac{\frac{1}{2} }{\frac{1}{8} } =4$

when share drops by $2 then share will be :

$27 - $2 =$25

and $\frac{3}{8} - 4(\frac{1}{8})$

⇒ $\frac{3}{8} - \frac{4}{8}$

⇒ $\frac{-1}{8}$

So, $25-\frac{1}{8}$

⇒ $24\frac{7}{8}$

So, its closing value is $24\frac{7}{8}$ .

7 0

3 years ago

A cookie recipe states for every 3 cups of flour, 1 1/2 teaspoons of vanilla are needed. How many teaspoons are needed for 5 cup

skad [1K]

3 / 1½ = 2 cups of flour per teaspoon

2x = 5
divide both sides by 2 to isolate x

x = 2.5

You need 2.5 teaspoons of vanilla for 5 cups of flour.

4 0

3 years ago

Can u please help me

Alchen [17]

Answer:

that answer u put is correct and r u in K12 to lol

8 0

3 years ago