The perimeter of the triangle would be B)18. the triangle's sides are equal and you can tell by the single lines on each side symbolizing that all the sides are equal. To find perimeter, you have to add all sides together, and in this case it is 6. When 6 is added three times, it equals 18, which is the answer.
9514 1404 393
Answer:
+70 or -70, depending on how you rewrite the equation
Step-by-step explanation:
A quadratic equation in standard form can be written as ...
ax² +bx +c = 0
When this equation is written in standard form, it could be either of ...
17x² +30x +40 = 0 . . . . . . . . . . add 17x²+30x to both sides
or
-17x^2 -30x -40 = 0 . . . . . . . . . subtract 40 from both sides
__
In the first case, a = 17, b = 30, c = 40 and (b+c) = 70.
In the second case, a = -17, b = -17, c = -40 and (b+c) = -70.
_____
<em>Additional comment</em>
I personally prefer a positive leading coefficient, but it is less work to subtract 40 from both sides than to subtract 2 terms from both sides. Check your curriculum materials for the preferred rewrite in this case.
Answer: 8(8p-3)
Step-by-step explanation:
64p and 24 are both divisible by 8
64p/8 = 8p
24/8 = 3
8(8p) - 8(3)
Distributive property
8(8p-3)
Answer: There are 24 traffic lights on Berry Boulevard.
Step-by-step explanation:
Since we have given that
Total length of road = ![4\dfrac{4}{5}=\dfrac{24}{5}\ miles](https://tex.z-dn.net/?f=4%5Cdfrac%7B4%7D%7B5%7D%3D%5Cdfrac%7B24%7D%7B5%7D%5C%20miles)
Number of roads on every
= 2
So, According to unitary method,
In every
, number of roads = 2
In every 1 mile, number of roads = ![\dfrac{5}{2}\times 2=5](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B2%7D%5Ctimes%202%3D5)
So, in every
the number of roads = ![\dfrac{24}{5}\times 5=24](https://tex.z-dn.net/?f=%5Cdfrac%7B24%7D%7B5%7D%5Ctimes%205%3D24)
Hence, there are 24 traffic lights on Berry Boulevard.
Answer:
x(t) = - 5 + 6t and y(t) = 3 - 9t
Step-by-step explanation:
We have to identify the set of parametric equations over the interval 0 ≤ t ≤ 1 defines the line segment with initial point (-5,3) and terminal point (1,-6).
Now, put t = 0 in the sets of parametric equations in the options so that the x value is - 5 and the y-value is 3.
x(t) = - 5 + t and y(t) = 3 - 6t and
x(t) = - 5 + 6t and y(t) = 3 - 9t
Both of the above sets of equations satisfy this above conditions.
Now, put t = 1 in both the above sets of parametric equations and check where we get x = 1 and y = -6.
So, the only set, x(t) = - 5 + 6t and y(t) = 3 - 9t satisfies this condition.
Therefore, this is the answer. (Answer)