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Anna35 [415]
3 years ago
7

Which material is a pure substance A Alloy B compound C mixture D solution?

Biology
1 answer:
svetlana [45]3 years ago
5 0

Answer:

compound

Explanation:

they are basically a 1 type atom, that can be broken down

or decomposed.

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Which allele combination represents a female who has a heterozygous sex-linked trait?
tiny-mole [99]

Answer:

"O XRXR" hope this helps xD

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3 years ago
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How many moles would there be in 100 g of glucose? In 500 g of glucose? SHOW WORK
vivado [14]

Answer:

a) 0.56moles

b) 2.78moles

Explanation:

The number of moles can be calculated by using the formula;

Mole (n) = Mass (M) ÷ Molar mass (MM)

For a glucose molecule, with chemical formula: C6H12O6

Where atomic mass of C= 12, H=1, O= 16

Molar mass of C6H12O6= 12(6) + 1(12) + 16(6)

= 72 + 12 + 96

= 180g/mol

a) In 100g of glucose;

Mole = 100/180

Mole = 0.56moles

b) In 500g of glucose

Mole = 500/180

Mole = 2.78moles

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3 years ago
Why do you think this is important for aquatic animals that live in very cold places?
Elenna [48]

Answer: here´s why

Explanation: Underneath the frozen upper layer, the water remains in its liquid form and does not freeze. Also, oxygen is trapped beneath the layer of ice. As a result, fish and other aquatic animals find it possible to live comfortably in the frozen lakes and ponds. If water is heated, its volume gradually decreases.

6 0
3 years ago
For each of the following, read the characteristics and then identify the kingdom. is mostly unicellular, eukaryotic, and is com
statuscvo [17]

Answer:

Explanation:

The first one is Prostista: Since they are mostly unicellular and are classified as eukaryotic.

The second one is Eubacteria: Since all Eubacteria has peptidoglycan in their cell walls.

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3 0
3 years ago
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If a population with two alleles is at Hardy-Weinberg equilibrium ad the frequency of one allele is 0.7, what is the heterozygot
Vinil7 [7]

Answer:

B. 0.42

Explanation:

Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1

According to the given information, the frequency of one allele in the population is= 0.7

This means that the frequency of the other allele would be= 1-0.7 = 0.3

Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42

4 0
3 years ago
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