The cell wall is the outside layer of the cell whereas the cell membrane is surrounds the cytoplasm of the cell.
Answer:
protein
Explanation:
because carbohydrate ..nucleic acids protein
Answer:
42,5 mL
Explanation:
We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.
<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>
The first step is to have the same measurment unit so we need to convert 345 µg to mg.
we know that 1 µg equals 0,001 g, hence:
now the final volume is 0,345 mg protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula
Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL
So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)
Answer:
Because it is only possible to be 100% sure that two species are closely related, in genetic terms, when the DNAs of these species can be analyzed. This analysis is only possible through molecular tests.
Explanation:
Molecular tests are bikini techniques that can analyze species at the molecular level, more specifically, these tests can deeply analyze the DNA (or RNA and proteins) of a species giving precise results on the molecule and allowing scientists to study it deep.
In studies, where the scientist wants to know how the species are genetically related, it is common for molecular tests to be introduced, as a way for the scientist to be 100% sure of the relationship between the species.
Answer:
<u>All the substrates are bound to the enzyme</u>, thats why the reaction rate stopped increasing.
Explanation:
Actually an enzyme works by binding a substrate molecule to its active site, producing a product , resulting in an increase in the rate of reaction.
Enzyme + substrate = Enzyme + product
Whenever enzymes are added , reaction rate increases as the substrates are being bound to the enzyme's active sites but then occurs a stage where further addition of enzyme cannot increase the reaction rate because all the substrates have bound to the enzyme and <u>there are no substrates left.</u> Hence the reaction rate stopped increasing.
