Complete Question:
A chemist prepares a solution of silver (I) perchlorate (AgCIO4) by measuring out 134.g of silver (I) perchlorate into a 50.ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the silver (I) perchlorate solution. Round your answer to 2 significant digits.
Answer:
13 mol/L
Explanation:
The concentration in mol/L is the molarity of the solution and indicates how much moles have in 1 L of it. So, the molarity (M) is the number of moles (n) divided by the volume (V) in L:
M = n/V
The number of moles is the mass (m) divided by the molar mass (MM). The molar mass of silver(I) perchlorate is 207.319 g/mol, so:
n = 134/207.319
n = 0.646 mol
So, for a volume of 50 mL (0.05 L), the concentration is:
M = 0.646/0.05
M = 12.92 mol/L
Rounded to 2 significant digits, M = 13 mol/L
Answer:
516.77 grams of Argon gas is present
Explanation:
Using the gas formula
PV = nRT
number of moles (n) = mass / molar weight or mass
P = pressure = 3.4 atm
V = volume = 72 L
R = gas constant = 0.082 L atm mol^-1 K^-1
T = temperature = 225 K
MM = molar mass of Ar = 38.984 g/mol
PV = mRT/ MM
m = PV MM / RT
m = 3.4 * 72 * 38.948 / 0.082 * 225
m = 9534.4704 / 18.45
m = 516.77 grams
the mass of Ar gas you have is 516.77 grams.
Answer:
B
Explanation:
it will not be waterproof anymore
Attached earlobes are recessive, and are represented with a lowercase
