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Anna11 [10]
3 years ago
12

Occasionally, a C¬H group can form a hydrogen bond. Why would such a group be more likely to be a hydrogen bond donor group when

the C is next to N
Chemistry
1 answer:
Anna [14]3 years ago
8 0

Answer:

Check explanation.(Last paragraph).

Explanation:

Hydrogen bond was used to account for the Behavior of some organic compounds containing Electronegative elements such as nitrogen and oxygen. It was proposed that, '' when a Hydrogen atom lies between two highly Electronegative atoms, it shows a unique property of forming a bond between them by holding one of the atoms by a covalent bond and the other by purely electrostatic force''. This electrostatic force is known as the hydrogen bonding.

===> So, let us now answer the question properly; C- H group would be more likely to be a hydrogen bond donor group when the C is next to N because their would be separation of charge in the adjacent C-H bond which is caused by the positively charged Nitrogen (N). This will cause a C^- and a H^+, that is partial negative and positive charges on carbon and Hydrogen respectively. With this, the ease at which hydrogen will donate will increase.

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At 150°C the decomposition of acetaldehyde CH3CHO to methane is a first order reaction. If the
Crank

The decomposition time : 7.69 min ≈ 7.7 min

<h3>Further explanation</h3>

Given

rate constant : 0.029/min

a concentration of  0.050 mol L  to a concentration of 0.040 mol L

Required

the decomposition time

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time

For first-order reaction :

[A]=[Ao]e^(-kt)

or

ln[A]=-kt+ln(A0)

Input the value :

ln(0.040)=-(0.029)t+ln(0.050)

-3.219 = -0.029t -2.996

-0.223 =-0.029t

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Explanation:

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When adding coefficients, you need to make sure that all of the elements stay balanced, not just one that you are trying to fix. I know that some equations are really difficult to balance, and when that is the case, there are equation balancing websites that can help out.

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