Answer:
Oxygen exists as a diatomic molecule in nature when it is not combined with any other element. It forms O2 molecule because it is stable when it is uncombined. ... By achieving octet configuration, the diatomic elements become more stable compared to the single atom. Therefore, oxygen and hydrogen are diatomic.
Explanation:
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Answer:
The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.
Explanation:

Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
We have mass of copper = m = 25.3 g
Specific heat of copper = c = 0.385 J/g°C
ΔT = 39°C - 22°C = 17°C
Heat absorbed by the copper :

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.
I would say that it is physical because there are no chemicals when the glass is breaking.
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Answer:
- The speed of the wave in the rope is 2 m/s
Explanation:
1. <u>Data</u>:
a) ν = 4 Hz
b) λ = 0.5 m
c) s = ?
2. <u>Physical principles and formula</u>:
The propagation of waves in a rope is a classical example of <em>transverse waves</em>: the pulse is inflected in the <em>vertical</em> direction and the wave travels in the <em>horizontal</em> direction, i.e. the pulse or vibration is perpendicular to the motion of the media particles.
The equation that relates <em>speed (s), wavelength (λ), frequency (ν) </em>is:
- wavelength = speed × period
- wavelenfth = speed / frequency
- meter = (meter/second) / second⁻¹
3. <u>Solution</u>:
Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj