The answer
the main formula is given by
Q=mSDT
where m= mass
s= specific heat
DT= <span>change in temperature
so Q = 50.89 x 1.8x 4.11 = 376.48</span>
The answer is electrons !. Hope it helps !! :)
Soowowowowlw,was the day that I was just trying to find out
Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
Methane CH4
ethane C2H6
propane C3H8
Butane C4H10
pentane C5H12
