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2 years ago

What is the difference between 24-karat gold and gold used for normal jewelry?

2 answers:

8 0

Answer: 24k gold has a higher purity making it softer and malleable but its used in jewelry as 14k and 18k gold of lesser purity

Explanation:

erastovalidia [21]2 years ago

4 0

Explanation:

A 24 Karat gold is 100 per cent pure gold and does not have any other metal mixed. ... The 24 karat gold is more expensive than 22 or 18 Karat gold. It is soft and pliable and that's why not used in making regular forms of jewellery

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A heavy textbook and a QOD journal sit on the edge of your desk. Which has more gravitational potential energy?

fenix001 [56]

The textbook Would most likely have more gravitational potential energy because it is heavier. Things that are heavier have a larger gravitational pull and are pulled to the earth faster

4 0

3 years ago

If 45.0 mL of ethanol (density = 0.789 g/mL) initially at 8.0 ∘C is mixed with 45.0 mL of water (density = 1.0 g/mL) initially a

strojnjashka [21]

Answer : The final temperature of the mixture is, $22.14^oC$

Explanation :

First we have to calculate the mass of ethanol and water.

$\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 45.0mL=35.5g$

and,

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g$

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of ethanol = $2.42J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of ethanol = 35.5 g

$m_2$ = mass of water = 45.0 g

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of ethanol = $8.0^oC$

$T_2$ = initial temperature of water = $28.6^oC$

Now put all the given values in the above formula, we get:

$35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.14^oC$

Therefore, the final temperature of the mixture is, $22.14^oC$

3 0

3 years ago

Using the two models, compare the processes of nuclear fusion and nuclear fission. What do the two processes have in common?

EleoNora [17]

Answer:it’s A and B

Explanation:

7 0

3 years ago

Read 2 more answers

What is the correct balanced equation for the reaction that occurs when aqueous ammonium chloride reacts with aqueous barium nit

Setler [38]

Answer:

$2NH_{4}Cl + Ba(NO_{3} )_{2}$ ⇒ $BaCl_{2} + 2NH_{4}NO_{3}$

Explanation:

In balancing a chemical equation we make sure the number of atoms of each element on the reactant side of the equation equals that on the product side

$NH_{4}Cl + Ba(NO_{3} )_{2}$ ⇒ $BaCl_{2} + NH_{4}NO_{3}$

The equation above represents an unbalanced equation of the reaction of aqueous ammonium chloride with aqueous barium nitrate .we can balance this equation by adding the right coefficients to reactants and product.

$2NH_{4}Cl + Ba(NO_{3} )_{2}$ ⇒ $BaCl_{2} + 2NH_{4}NO_{3}$

5 0

3 years ago

How many joules are required to melt 100 grams of water? The heat of

vova2212 [387]

Answer- 33.4 kJ

Explanation-

100 g H2O x (1mol/18g) = 5.5 mol

q=(5.5 mol)(6.01 KJ/mol)= 33.4 kJ

4 0

3 years ago