P1V1=P2V2
(1.00atm)(3.60L)=(2.50atm)V
3.60=(2.50atm)V
3.60/2.50=V
1.44L=V
Answer:
≅ 16.81 kJ
Explanation:
Given that;
mass of acetone = 31.5 g
molar mass of acetone = 58.08 g/mol
heat of vaporization for acetone = 31.0 kJ/molkJ/mol.
Number of moles = 
Number of moles of acetone =
Number of moles of acetone = 0.5424 mole
The heat required to vaporize 31.5 g of acetone can be determined by multiplying the number of moles of acetone with the heat of vaporization of acetone;
Hence;
The heat required to vaporize 31.5 g of acetone = 0.5424 mole × 31.0 kJ/mol
The heat required to vaporize 31.5 g of acetone = 16.8144 kJ
≅ 16.81 kJ
These answers dont make sense
1. the 2s2 orbital will give one of its electrons to the 2p5 orbital so the configuration would be 1s22s12p6 (2s1 is half filled and 2p6 is completely filled which is a much more stable configuration)
2. Neon does not need to ionize it is a noble gas
Answer:
H2CO3 = 2H+ + CO3-
Explanation:
It is simply what carbonic acid breaks down into when placed in water. Since carbonic acid is made up of H and CO3, these are the products.