Greetings!
When reflecting a shape over the x-axis, you simply change the number to its opposite positive/negative equivalent.
This means that the new co-ordinates would be (-5,1) , (-5,4) and (-2,4).
Hope this helps!
Hi there!
We know that the equation for the volume of a pyramid is:
V = 1/3(bh)
We know that:
V = 200 km³
b = 12 × 5 = 60 km²
We can plug these into the equation:
200 = 1/3(60)(h)
Simplify:
200 = 20h
Divide both sides by 20:
200/20 = 20h/20
h = 10 km
You have the correct answer. It is choice A. Nice work.
I prefer using full circles because sometimes the arcs could be too small in measure to not go where you want them to. If you're worried about things getting too cluttered (a legitimate concern), then I recommend drawing everything in pencil and only doing the circles as faint lines you can erase later. Once the construction is complete, you would go over the stuff you want to keep with a darker pencil, pen or marker. You can also use the circle as a way to trace over an arc if needed.
Choice B is false as a full circle can be constructed with a compass. Simply rotate the compass a full 360 degrees. Any arc is a fractional portion of a circle.
Choice C is false for similar reasoning as choice B, and what I mentioned in the paragraph above.
Choice D contradicts choice A, so we can rule it out. Arcs are easier to draw since it takes less time/energy to rotate only a portion of 360 degrees. Also, as mentioned earlier, having many full circles tend to clutter things up.
Answer:
The coordinates of ABCD after the reflection across the x-axis would become:
Step-by-step explanation:
The rule of reflection implies that when we reflect a point, let say P(x, y), is reflected across the x-axis:
- x-coordinate of the point does not change, but
- y-coordinate of the point changes its sign
In other words:
The point P(x, y) after reflection across x-axis would be P'(x, -y)
P(x, y) → P'(x, -y)
Given the diagram, the points of the figure ABCD after the reflection across the x-axis would be as follows:
P(x, y) → P'(x, -y)
A(2, 3) → A'(2, -3)
B(5, 5) → B'(5, -5)
C(7, 3) → C'(7, -3)
D(5, 2) → D'(5, -2)
Therefore, the coordinates of ABCD after the reflection across the x-axis would become:
