For part A: the constant is 83.50. the variable would be c and w. and the coefficient would be 10c or 15w.
part B: so 10(4)+15(15)+83.50 -----> 10x4= 40------> 40+15(15)+83.50---->15x15=225
40+225+83.50=348.50
part C The coefficient would change because a constant is always constant, a variable is just a letter standing in for a number which would make the coefficient the one that changes for $10 to $20.
hope that help!
Answer:
See the proof below.
Step-by-step explanation:
We are assuming that A is not square. So let's assume that A is an axb matrix that is not square because ![a \neq b](https://tex.z-dn.net/?f=%20a%20%5Cneq%20b)
Since is a not square matrix then A needs to has more rows than columns case 1 (a>b) or more columns than rows case 2 (n>m)
Case 1 (a>b)
We need to remember that the dimension for the row space is
with b the number of columns.
The a row vectors conform a set with more vectors than the dimension of the b dimensional space
where the vectors exists. So then the vectors are linearly dependent.
Case 2(b>a)
We need to remember that the dimension for the colum space is
with a the number of rows.
The b column vectors conform a set with more vectors that the dimension of the a dimensional space
where the vectors exists. So then the vectors are linearly dependent.
So for both cases when we don't have a square matrix then either the row vectors of A or the column vectors of A form a linearly dependent combination.
One I love your answer but the real but i think it is (-1,3)