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Dimas [21]
3 years ago
9

Please help! I am stuck

Mathematics
1 answer:
marta [7]3 years ago
8 0
A. 27. 
we can prove that the two triangles within the triangle are congruent (the triangle is an isosceles) with SAS. then we do 180- (63 x 2). then we get the top angle. and then we divide 54 by 2 to make the individual angles and then we get 27. 
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Which number is rational? 2 square root, pi ,10 square root ,16 squeare root
ki77a [65]

Answer:

Square root of 16 is rational beacuse Square root of 16=4 Whlie the others are Irational.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help!<br><br> Find the slope<br><br> -2x + 4y = 36<br><br> Thank you!
kogti [31]
-2x+4y=36
Add +2x to both sides
4y=2x+36
Decide every term by 4
y= 2/4x + 9

The slope is 2/4
8 0
3 years ago
Describe the graph of a system of equations that has no solution.
Thepotemich [5.8K]

<span>The solution for a system of equations is the value or values that are true for all equations in the system. The graphs of equations within a system can tell you how many solutions exist for that system. Look at the images below. Each shows two lines that make up a system of equations.</span>

 

<span><span>One SolutionNo SolutionsInfinite Solutions</span><span /><span><span>If the graphs of the equations intersect, then there is one solution that is true for both equations. </span>If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations.</span></span>

 

When the lines intersect, the point of intersection is the only point that the two graphs have in common. So the coordinates of that point are the solution for the two variables used in the equations. When the lines are parallel, there are no solutions, and sometimes the two equations will graph as the same line, in which case we have an infinite number of solutions.

 

Some special terms are sometimes used to describe these kinds of systems.

 

<span>The following terms refer to how many solutions the system has.</span>

5 0
3 years ago
Need answer to 4 and 5
algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
I have to redo this test and I'm stuck on this question. Please help and please show work.
nexus9112 [7]
This is the answer hope this helped u

5 0
3 years ago
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