All categories

2 years ago

100 megatons+234 help please

Mathematics

1 answer:

arlik [135]2 years ago

6 0

Answer:

we know,

1 megaton=1000kg

100 megaton=100000

now,

total weight=100000+234

=100234.

You might be interested in

Is it true that the constant of the expression 18z-7(-3+2z) is 21

ZanzabumX [31]

Yes. It would be true

7 0

2 years ago

Write the equation of the line with the given slope through the given point Slope = 6; (1, 2).

xz_007 [3.2K]

Answer:

Y=6x-4

Step-by-step explanation:

Y=mx+b

in this cace we have m- the slope

Y=6x+b

now we can plug in the coordinates to solve for b- the y intercept

(1,2) 1 being the x value, and 2 being the y value

2= 1·6+b

2=6+b

-4=b

now we take our previous equation, and add to it

Y=6x-4

4 0

3 years ago

What are the solutions to. x^2 - x - 20 = 0

nignag [31]

Step-by-step explanation:

x² - x - 20 = 0

x² - (5-4) x - 20 = 0 

x² - 5x + 4x -20 = 0

x ( x - 5) + 4 ( x - 5) = 0

(x - 5) (x+ 4) = 0

Either. 

x - 5 = 0

x = 5

Or, 

x + 4 = 0 

x = -4

3 0

3 years ago

A group of winning ticket holders share equally 90,000,000 lottery. Before the money is divided, three more winning ticket holde

Kruka [31]

Let's assume

people were in the original group of winners as x

A group of winning ticket holders share equally 90,000,000 lottery

Before the money is divided, three more winning ticket holders are declared

so, total number of winning tickes =x+3

each persons share is reduced to 5,000,000

so, total money =5,000,000*(x+3)

and this must be equal to total money

$5000000(x+3)=90,000,000$

now, we can solve for x

and we get

$x+3=18$

Subtrac both sides by 3

$x+3-3=18-3$

$x=15$

so,

number of people were in the original group of winners is 15 ...........Answer

6 0

2 years ago

dale has a square garden. He adds a 2-foot-wide walkway around his garden. If the total area of the walkway and garden is 196 sq

dem82 [27]

Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:

1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.

The total walkway area is thus x^2 + 4(2^2) + 4(x*2).

We want to find the dimensions of the garden. To do this, we need to find the value of x.

Let's sum up the garden dimensions and the walkway dimensions:

x^2 + 4(2^2) + 4(x*2) = 196 sq ft

x^2 + 16 + 8x = 196 sq ft

x^2 + 8x - 180 = 0

(x-10(x+18) = 0

x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.

4 0

3 years ago