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Kay [80]
3 years ago
11

A milk booth sells 448 litres of milk in a day. How many litres of milk will it sell in 5 days?

Mathematics
2 answers:
Colt1911 [192]3 years ago
7 0

Answer:s

Step-by-step explanation:

i can see you

Vlad1618 [11]3 years ago
4 0

Answer:

2240 liters

Step-by-step explanation:

448 multplied by 5 is equal to 2240 liters.

8 multplied by 5 is 40.

40 multplied by 5 is 200.

400 multplied by 5 is 2000.

2000 + 200 + 40 = 2240.

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Step-by-step explanation:

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The Johnson family had a 4,392-gallon swimming pool installed last month. They are filling the pool at a rate of 2 pints per sec
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Find the equation of a line that contains the points (3,7) and (-6, 4). Write the equation in slope-intercept form, using
NikAS [45]

Answer:

y=\frac{1}{3} x+6

Step-by-step explanation:

(3,7)(-6,4)

Step 1. Find the slope (by using the slope-formula)

m = slope

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{4-7}{-6-3}

m=\frac{-3}{-9}

m=\frac{3}{9}

m=\frac{1}{3}

Step 2. Write the equation (using the slope and the points)

Here's how to do it:

Slope-intercept Formula y=mx+b whrere m = slope and b = y-intercept

Plug in the slope into the Slope-intercept Formula

y=\frac{1}{3} x+b

Find the y-intercept (b) by using a point and substituting their x and y values

y=\frac{1}{3} x+b

Point: (3, 7)

7=\frac{1}{3} (3)+b

7=1+b

b=7-1

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Step 3. Write the equation in Slope-intercept form

y=mx+b

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3 0
3 years ago
A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 21.5, \sigma = 4.7

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.175*4.7

X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.04*4.7

X = 26.388

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0
4 years ago
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