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emmasim [6.3K]
3 years ago
12

What is 2Log5(5x^3)+1/3log5(x^2+6 written as a single logarithm?

Mathematics
2 answers:
AveGali [126]3 years ago
5 0

An important rule of logs is a*log b = log b^a.

Thus, 2 (log to the base 5 of )(5x^3) = (log to the base 5 of ) (5x^3)^2, or

(log to the base 5 of ) (25x^6).

Next, (1/3) (log to the base 5 of ) (x^2+6) = (log to the base 5 of ) (x^2+6)^(1/3).

Here, the addition in the middle of the given expression indicates multiplication:

2Log5(5x^3)+1/3log5(x^2+6) = (log to the base 5 of ) { (5x^3)^2 * (x^2+6)^(1/3) }.

Here we've expressed the given log quantity as a single log.

Vikentia [17]3 years ago
4 0

Answer: B on Edge. log5 (25x^6) 3 sqrt x^2+8. Hope this helps!

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