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3 years ago

Solve for x: k=3x+2/x-1

Mathematics

1 answer:

Anna11 [10]3 years ago

3 0

Answer:

x = (2+k)/(k-3)

Step-by-step explanation:

k = (3x +2)/(x-1)

First just multiply both sides by (x-1)

(x-1)k = 3x+2

kx - k = 3x+2

Add k both sides and Subtract 3x both sides to get:

kx - 3x = 2+k

Take x out since it's common

x(k-3) = 2+k

Multiply both sides by (k-3)

x = (2+k)/(k-3)

Hope this helps!

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HELP me with this so i dont held back

Brrunno [24]

Answer:

1)2/3

2) 3/2

Step-by-step explanation:

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2 years ago

The sum of these fractions is between which two whole numbers? 3 4/6 1 3/6 4&5 5&6 6&7 or 7&8

umka21 [38]

<span>3 4/6 + 1 3/6 = 4 7/6 = 5 1/6
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3 years ago

What is -2¾ as a decimal

gtnhenbr [62]

Answer:

-2 $\frac{3}{4}$ is equal -2.75 as a decimal

Step-by-step explanation:

to take -2 $\frac{3}{4}$ to decimal, we take -2 and put point behind it. by doing so, $\frac{3}{4}$ becomes 300/4=75

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2 years ago

Read 2 more answers

Prove that ΔABC and ΔEDC are similar.

Lesechka [4]

Answer:

∠DCE is congruent to ∠CBA by the Vertical Angles Theorem and 15 over 5 equals 12 over 4 shows the corresponding sides are proportional; therefore, ΔABC ~ ΔEDC by the SSS Similarity Postulate.

Step-by-step explanation:

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2 years ago

Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams. Three players in each team how many different

IgorC [24]

Answer:

$20$

Step-by-step explanation:

GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.

TO FIND: how many different ways can they be put into two teams of three players.

SOLUTION:

Total number of players $=6$

total teams to be formed $=2$

total players in one team $=3$

we have to number of ways of selecting $3$ players for one team, rest $3$ will go in other team.

Total number of ways of selecting $3$ players $=^6C_3$

$=\frac{6!}{3!3!}$

$=20$

Hence total number of different ways in which they can be put into two different teams is $6$

5 0

3 years ago