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3 years ago

Solve for x: k=3x+2/x-1

Mathematics

1 answer:

Anna11 [10]3 years ago

3 0

Answer:

x = (2+k)/(k-3)

Step-by-step explanation:

k = (3x +2)/(x-1)

First just multiply both sides by (x-1)

(x-1)k = 3x+2

kx - k = 3x+2

Add k both sides and Subtract 3x both sides to get:

kx - 3x = 2+k

Take x out since it's common

x(k-3) = 2+k

Multiply both sides by (k-3)

x = (2+k)/(k-3)

Hope this helps!

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Answer:

A=60

Step-by-step explanation:

Add 28+20+12

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3 years ago

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Help urgent, which functions are bounded below but not above? Choose all answers that apply.

evablogger [386]

Answer:

c, e, f, and i

Step-by-step explanation:

a. is bounded above at y = 1 and below at y = 0

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3 years ago

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3 years ago

A 30-N stone is dropped from a height of 10 m and strikes the ground with a speed of 13 m/s.

Anon25 [30]

Answer:

4.1 N

Step-by-step explanation:

We can solve this problem by using considerations about energy.

At the moment the stone is dropped, it has only gravitational potential energy:

$PE=mgh$

where

$mg=30 N$ is the weight of the stone

h = 10 m is the initial height of the stone

As the stone falls, part of this energy is converted into kinetic energy, while part into thermal energy due to the presence of the air friction, acting opposite to the motion of the stone:

$KE+E_t = \frac{1}{2}mv^2 + E_t$

where:

$m=\frac{mg}{g}=\frac{30}{9.8}=3.06 kg$ is the mass

v = 13 m/s is the final speed of the stone

$E_t$ is the thermal energy

The thermal energy is actually equal to the work done by the air friction on the stone:

$E_t=W=Fh$

where

F is the average force of friction

h = 10 m

Since the total energy must be conserved, we can combine the three equations, so we find:

$mgh=\frac{1}{2}mv^2+Fh$

And solving for F, we find the average force of air friction:

$F=\frac{mgh-0.5mv^2}{h}=\frac{(30)(10)-0.5(3.06)(13)^2}{10}=4.1 N$

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3 years ago

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amm1812

9:1 because you divide both sides by 8. Hope this helps :)

3 0

3 years ago