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olga55 [171]
3 years ago
9

Shelly is trying to improve her running time for a track race. She ran the first race in 43.13 seconds. Her time was 43.1 second

s in the second race and 43.07 seconds in the third race. If this pattern continues what will shellys time be in the fourth race?
Mathematics
1 answer:
saul85 [17]3 years ago
8 0
<h3>The time in fourth race is 43.04 seconds</h3>

<em><u>Solution:</u></em>

Given that,

Shelly is trying to improve her running time for a track race

She ran the first race in 43.13 seconds

Her time was 43.1 seconds in the second race and 43.07 seconds in the third race

<em><u>Therefore, pattern is:</u></em>

43.13, 43.1, 43.07 , ..

<em><u>Find the difference between each terms</u></em>

d = 43.13 - 43.1 = 0.03

d = 43.1 - 43.07 = 0.03

Thus the difference is same

<em><u>If this pattern continues what will shellys time be in the fourth race?</u></em>

Fourth race = third race - 0.03

Fourth race = 43.07 - 0.03 = 43.04

Thus the time in fourth race is 43.04 seconds

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