I cant see the question, id help if i could
Um, so it's a bit awkward with this question because they actually got the x value incorrect. When they added up all the values, they got 9x - 27 = 180, but it's actually 9x + 27 = 180 because -18 + 45 is positive 27. Anyways, when you solve it correctly you get x = 17, and then you substitute it into the angles. So with 5x - 18, you are saying 5(× 17) - 18 = 67. Then with the other one you do 4(× 17) + 45 = 113. You know that x is definitely 17 because 113 + 67 = 180.
Answer:
The answer to your questions are in bold
Step-by-step explanation:
a)
C = ![\left[\begin{array}{ccc}-6&6\\-2&4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%266%5C%5C-2%264%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= -24 + 12
= -12
b) -1 7 -4 -1 -1 - 4 7 - 1 - 5 6
-2 -6 -8 8 = -2 - 8 -6 + 8 -10 2
2 -3 2 -7 2 + 2 -3 - 7 4 -10
-1 10 -6 5 -1 - 6 10 + 5 -7 15
9514 1404 393
Answer:
- one: x+3 = 2x
- none: x+3 = x
- infinite: x+3 = x+3
Step-by-step explanation:
A linear equation with variable terms on opposite sides of the equal sign will have one solution when the coefficients of those variables are different.
x+3 = 2x . . . . has one solution (x=3)
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There will be no solution if the variable terms on opposite sides of the equal sign have the same coefficient, but the constants are different. Such an equation can be reduced to 0 = 1, which cannot be made true by any value of the variable.
x +3 = x . . . . has no solutions
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There will be an infinite number of solutions if the left side of the equal sign is the same as the right side. Every value of the variable will satisfy the equation.
x +3 = x +3 . . . . has infinite solutions