Answer:
yes
Step-by-step explanation:
Answer:
2<x<4/3
Step-by-step explanation:
Given the equation of a graph to be y = |3x− 5|, if the equation is one unit to the right, this can be expressed as |3x-5| > 1.
Solving the resulting equation
|3x-5| > 1.
Since the function 3x-5 is in a modulus sign, this means that the function can take both negative and positive values.
For positive value of the function;
+(3x-5) > 1
3x > 1+5
3x>6
x>6/3
x>2 ... (1)
For the negative value of the function;
-(3x-5) > 1
On expansion
-3x+5 > 1
-3x > 1-5
-3x > -4
Multiplying through by -1 will also change the inequality sign
x < -4/-3
x < 4/3...(2)
Combining equation 1 and 2, we have;
2<x<4/3
YOU DON"T HAVE TO YELL
512 PER STUDENT
BASICALLY,
CUBES NEEDED=CUBES PER STUDENT TIMES NUMBER OF STUDENTS
NUMBER OF STUDENTS=28+25=53
CUBES PER STUDENT=512
CUBES NEEDED=512 TIMES 53 EQUALS 27136 CUBES
SHE NEEDS 27136 CUBES FOR ALL HER STUDENTS
f(x)=5x-3
use the substitution method
f(5)=(5)(5)-3
multiply the parentheses first
using: PEDMAS
P=Parentheses
E= Exponents
D=Division
M=Multiplication
A= Addition
S=Subtraction
(5)(5)=25
25-3
=22
answer:
f(5)=22