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3 years ago

Evaluate f(x)=5x-3 f(5) =

Mathematics

1 answer:

Kaylis [27]3 years ago

5 0

f(x)=5x-3

use the substitution method

f(5)=(5)(5)-3

multiply the parentheses first

using: PEDMAS

P=Parentheses

E= Exponents

D=Division

M=Multiplication

A= Addition

S=Subtraction

(5)(5)=25

25-3

=22

answer:

f(5)=22

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5) A cab driver uses 36 gallons of gas in driving 529.2 miles. Find the

Sati [7]

Answer:

14.7 miles per gallon

Step-by-step explanation:

All you have to do is divide the number of miles by the number of gallons to find out how many miles are driven per gallon of gas. Hope I helped!

6 0

3 years ago

Read 2 more answers

Part A: Joel uses the incorrect expression 0.95(190)(0.8) to calculate that the computer will cost him a total of $144.40. Descr

notka56 [123]

Answer:

Part A) The correct Expression : (1.05)(190)(0.8)

=> The error of Joel was that instead of adding the sales tax, he subtracted it.

Part B) $159.60

Step-by-step explanation:

Part A:

To calculate the computer cost, we need to find out the selling price first.

There's a discount of 20% so the selling price will be 100% - 20% = 80% =>80/100 = 0.8

So, We'll multiply the cost price by 0.8

=> (190)(0.8)

But, there is a sales tax of 5%

So, the selling price with cost price will be:

=> 100% + 5% = 105% => 105/100 = 1.05 (We'll multiply this too with the first equation that we made above)

So, the expression will be:

=> (1.05)(190)(0.8)

The error of Joel was that instead of adding the sales tax, he subtracted it.

Part B)

Joel will pay for the tablet:

=> (1.05)(190)(0.8) [We used the above expression]

=> $159.60

6 0

3 years ago

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

3 years ago

At the beginning of the week Fayez writes drown the mileage of his limousine - 2529 At the end of the week the mileage is 2834,

Alexandra [31]

2834 - 2529 = 305 miles traveled
75.2 / 4.64 = 16.4 gallons used
305 / 16.4 = 18.5 miles per gallon
The limo did not use 1 gallon every 20 miles.
The limo used 1 gallon every 18.5 miles

4 0

3 years ago

Are of circle find.

Andreas93 [3]

Answer:

379.94

Step-by-step explanation:

11 squared is 122

Times 3.14 is 379.94

5 0

2 years ago