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3 years ago

Which shape has a larger area: a rectangle that is 7 inches by 34 inch, or a square with side length of 212 inches?

Mathematics

2 answers:

GREYUIT [131]3 years ago

7 0

Answer is square with the side of 212 inches. It's area is 212×212 which is bigger than rectangular area.

MA_775_DIABLO [31]3 years ago

5 0

Area of the rectangle = 7 * 34 = 238 in^2

Area of square = 212^2 = 44944 in^2

The square has the larger area.

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Which answer describes the calculations that could be used to solve this problem?

Zanzabum

THe answer to ur problem is:

A

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3 years ago

Read 2 more answers

janelle wishes to finance a car for $33,000. the bank's annual interest rate is 3.5%, and she can choose between durations of fi

Harman [31]

Answer:

For a duration of 5 years, Monthly Payment =$600.42

For a duration of 6 years, Monthly Payment =$508.83

Step-by-step explanation:

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\$

where a= Amount to Finance=$33,000

Annual interest rate = 3.5%=0.035

r=Monthly Interest Rate= 0.035 ÷ 12 = $\frac{7}{2400}$

n=number of months to pay

For a duration of 5 years

n=5X12=60 months

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\\\P=\dfrac{33000 X\frac{7}{2400} (1+\frac{7}{2400} )^{60}}{(1+\frac{7}{2400})^{60}-1} \\=\dfrac{96.25 (1.1909)}{1.1909-1}\\=\dfrac{96.25 (1.1909)}{0.1909}\\=\dfrac{114.62}{0.1909}=\$600.42$

For a duration of 6 years

n=6X12=72 months

$P=\dfrac{ar (1+r)^n}{(1+r)^n-1} \\\\P=\dfrac{33000 X\frac{7}{2400} (1+\frac{7}{2400} )^{72}}{(1+\frac{7}{2400})^{72}-1} \\=\dfrac{96.25 (1.2333)}{1.2333-1}\\=\dfrac{96.25 (1.2333)}{0.2333}\\=\dfrac{118.71}{0.2333}=\$508.83$

4 0

3 years ago

Solve the inequality. Show your work. |r + 3| ≥ 7

poizon [28]

R could equal any number, but it has to be higher than 4, because 3+4=7.

7 0

3 years ago

X+a=3/4 I don't know how to solve this and I need someone to help explain it to me.

Aneli [31]

I think you should Subtract
a
a
from both sides of the equation.
x=3/4-a and that’s your answer

8 0

3 years ago

Given f(x)=2a^2b+3a^3b^2+2a^2b^4 what is the degree?

lilavasa [31]

We have the following function:
f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
We note that the function depends on x because it is f (x).
However, there is no variable x in the function.
Therefore we can assume that the function is constant, since:
a = constant
b = constant
Therefore, the degree of the function is zero
Answer:
The function is zero degree.

7 0

3 years ago