13 3/39 is too big, it's greater than 9, so that one is out.
16 is an integer, so that one is out too. 99/6 = 16.5, which is greater than 9, so it can't be right
So the answer is the other 3
Answer:
Step-by-step explanation:
f(x) = 4-x
g(x) = h
+k
g(f(x)) = 2-16x+26
so put f(x) in g(x)
h
+k
h((4-x)(4-x) + k
h(-8x+16)+k
if h = 2 , then
2-16x+32 + k
and we want 26 instead of 32 so subtract 6 so K = (-6)
2-16x+32 + (-6)
2-16x+32 - 6
2-16x+26
h=2
k=(-6)
Answer:
36 degrees
Step-by-step explanation:
since, m<AOB is a right angle, we shall just create an equation:
M<AOB+M<BOC=90 degrees
Substitute: 6z-12+3z+30=90
Solve: 6z+3x=9z
-12+30=18
so, 9z+18=90 degrees
-18 -18
9z=72
z=8
So if z=8, then we should fit it so that it matches measure of AOB.
6z-12
6 times 8=48
48-12= 36
Answer:
D. -17/2
Step-by-step explanation:
1/2 - 4 (1/2 + 1)^2
First we evaluate what is inside the parentheses
1/2 - 4 (3/2) ^2
Now we square what is inside the parentheses
1/2 - 4(9/4)
Now multiply
1/2 -9
Get a common denominator 9 = 9 *2/2 = 18/2
1/2 - 18/2
-17/2
Answer:
D: (-1,2)
Step-by-step explanation:
The X coordinate is between 2 and -4. There is a difference of 6, so you should do -4 + (6/2) = -1.
so the X coordinate is -1
The y coordinate is between 0 and 4. There is a difference of 4, so you should do 0 + (4/2) = 2.
so the y coordinate is 2
This results in the centre being (-1,2)
