Need please solving for x

Mathematics

1 answer:

koban [17]2 years ago

6 0

Answer:

x = 15

Step-by-step explanation:

Corresponding sides of similar shapes are proportional to each other. Thus:

(10 + 2)/10 = (x + 3)/x

12/10 = (x + 3)/x

Cross multiply

12*x = (x + 3)*10

12x = 10x + 30

12x - 10x = 30

2x = 30

x = 30/2

x = 15

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3 years ago

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Alona [7]

Answer:

$\large\boxed{1.\ (4)^{-3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}}$

$\large\boxed{2.\ ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x}$

Step-by-step explanation:

$Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\\------------\\\\(4)^{-3x^2}=\left[(4)^{-1}\right]^{3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}$

$Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\ and\ (a^n)^m=a^{nm}\\--------------------\\\\ab^{-3x}=a\cdot b^{-3x}=a\left[(b)^{-1}\right]^{3x}=a\left(\dfrac{1}{b}\right)^{3x}\\\\ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x$