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Rufina [12.5K]
3 years ago
15

Which point is located in Quadrant ll?

Mathematics
1 answer:
iVinArrow [24]3 years ago
8 0
(-4,5) because the Quadrants are in the shape of a C. -4 on the x-axis is the left side of the x-axis, and 5 is on the y-axis going up. If you follow to where -4 on the x-axis and 5 on the y-axis meet, you will get a point in the top left quadrant aka quadrant 2.
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Please help please please
Slav-nsk [51]

Answer: -1.5 <= x < 1

Solution

The domain of the function is the values that the valriable x can take. According with the graph the variable x can take values between -1.5 (including because of the black point) and 1 (excluding because of the white point), then:

-1.5 <= x < 1

7 0
3 years ago
Read 2 more answers
A fishing lodge wants to build a new boat ramp. The slope of the ramp must be 8° to the horizontal. The total height of the bank
Likurg_2 [28]

Answer:

The length of the sloping section of the ramp is 20.12 m

Step-by-step explanation:

Given;

the total height of the bank, h = 2.8 m

The slope of the ramp must be 8° to the horizontal, i.e, θ = 8°

Let the length of the sloping section = L

let the horizontal distance between the height of the bank and sloping section = b

Thus, h, L and b forms three sides of a right angled-triangle, with L as the hypotenuse side, h  (height of the triangle) as the opposite side and b  (base of the triangle) as the adjacent side.

We determine L by applying the following formula;

Sinθ = opposite / hypotenuse

Sin θ = h / L

L = h / Sin θ

L = 2.8 / Sin 8

L = 2.8 / 0.13917

L = 20.12 m

Therefore, the length of the sloping section of the ramp is 20.12 m

6 0
3 years ago
9x^2(y^5)/3xy^7 simplify
Ghella [55]

Answer:

( 9x^2y^5 /3  x)(y^7)

=3x^3y^12

6 0
3 years ago
What is a parallel line to y= -2/3x+3
Natali5045456 [20]

Answer:

-2/3

Step-by-step explanation:

because this is in slope intercept form, m is the slope, so in this case -2/3 is the slope

parallel lines always have the same slope and different y-intercepts

a parallel line could be y=-2/3 +15

4 0
4 years ago
Marie has a small copy of Rene Magritte's famous painting, The Schoolmaster. Her copy has dimensions 2 inches by 1.5 inches. The
avanturin [10]
A scale of 1:40 can be read as "one cm on the model corresponds to 40 cm in the original object". or 

"one inch on the model corresponds to 40 inches
this means that  the 2 inches correspond to 2 times 40, that is 80 inches and 1.5 corresponds to 1.5*40=60 inches

which means that the original painting has dimensions of 80 by 60 inches.
b) Area = 80 cm * 60 cm = 4,800 cm²
c) 80 cm * 1 inch / 2.54 cm = 31.50 inches ; 
    60 cm * 1 inch/2.54 cm = 23.60 inches
d) Area = 31.50 in * 23.60 in = 743.40 inches² 
5 0
3 years ago
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