All categories

3 years ago

Where does a median drawn from a vertex of a triangle intersect?

2 answers:

vladimir2022 [97]3 years ago

4 0

A median is a line that originates from a vertex of a triangle and ends on the opposite side, dividing the opposite side into two. Thus, the median intersects the opposite side at its midpoint. The answer to this item is letter B.

storchak [24]3 years ago

4 0

Answer:

option:B

Step-by-step explanation:

" A median is a line that originates from a vertex of a triangle and ends on the opposite side,dividing the opposite sides into two. Thus, the median intersects the opposite side at it's mid-point ".

Hence, based on the definition of median drawn from a vertex of a triangle option B is correct.

You might be interested in

Write the compound inequality shown by the graph.

Anni [7]

9 > x >= 2 is the answer

6 0

3 years ago

The volume of a right circular cone with radius r and height h is V = pir^2h/3.

Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9 and dr = 6.8 - 5.9 = 0.9

h = 4 and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b). The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47 and dr = 6.45 - 6.47 = -0.02

h = 10 and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0

3 years ago

Why is the absolute value of every number positive

bekas [8.4K]

Answer:

because you can't get closer to 0 on the number line than 0 units away.

Step-by-step explanation:

it's like walking if the point is 3 foot in front of you and you walk to it once you get to it then even if you keep walking you can't go a negative number of feet away from it because the closest you can get is right on it.

7 0

4 years ago

Indira is using a number line to add –1 + (–3). She begins by showing –1 on the number line, as shown below. What is the sum of

Naddik [55]

The answer is -4, because -1+-3=-4

5 0

3 years ago

Read 2 more answers

Please help me i really need help please

maw [93]

Answer:

39°

Step-by-step explanation:

IM assuming xyz is a triangle

180 - 113 - 28 = 67 - 28 = 39

3 0

3 years ago