Magnesium and nitrogen react in a combination reaction to produce magnesium nitride: 3 Mg + N2 → Mg3N2 In a particular experimen
1 answer:
Answer:
The mass of Mg consumed is 23.76 g.
Explanation:
Magnesium and nitrogen react as : three moles of magnesium reacts with one mole of nitrogen to give one mole of magnesium nitride.
as given that the mass of nitrogen reacted = 9.27 g
moles of nitrogen reacted =
Thus moles of magnesium reacted = 3 X 0.33 = 0.99 moles
mass of Mg reacted = moles X atomic mass = 0.99 X 24 = 23.76 grams
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<u>Answer:</u>
2.07 grams
<u>Explanation:</u>
We know that the molecular mass of is 138.205 grams.
In order to find out how many grams we need to make 200 mL having a potassium ion concentration of 0.150, we need to find the number of moles first.
M = moles / liters
0.150 = x / 0.200
x = 0.03 moles
Since there are 2 potassium atoms in each molecule of so we will divide this number by half and multiply it by the molecular mass.
0.03/2 = 0.015 moles
Mass of needed = 0.015 × 138.205 = 2.07 grams