Answer:
the answer is b Li + Cl2 .....
Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj
Answer:
<h3>The answer is 0.91 %</h3>
Explanation:
The percentage error of a certain measurement can be found by using the formula
From the question
actual volume = 198.2 mL
error = 200 - 198.2 = 1.8
So we have
We have the final answer as
<h3>0.91 %</h3>
Hope this helps you
Answer: 157.8 g
Explanation: I hope this help my child UwU
What is the weight of the ethyl alcohol that exactly fills a 200.0 mL container the density of ethyl alcohol is 0.789 g ml?
Density review
A
B
What is the weight of the ethyl alcohol that exactly fills a 200.0 mL container? The density of ethyl alcohol is 0.789 g/mL.
g = (0.789 g/mL) (200.0 mL) = 158 g
