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1 year ago

NEED HELP PLEASE HURRY

Chemistry

1 answer:

baherus [9]1 year ago

7 0

Answer:

I believe it would be the last 2

Explanation:

the 4th one is magnesium and something else but that's with decomposition and so is the last one. the first three has water and oxygen and stuff that doesn't rly do decomposition

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The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.070% by weight. If a 21.5 g sample of this

Semmy [17]

Answer:

The molar concentration of $Cu^{2+}$ ions in the given amount of sample is $4.73\times 10^{-5}M$

Explanation:

Given that,

Mass of sample = 21.5 g

0.07 % (m/m) of copper (II) sulfate in plant fertilizer

This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present

So, in 20 g of plant fertilizer

, $=\frac{0.07}{100}\times 21.5}\\=0.0151g$ of copper (II) sulfate is present.

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Mass of solute (copper (II) sulfate) = 0.0151 g

Molar mass of copper (II) sulfate = 159.6 g/mol

Volume of solution = 2.0 L

$\text{Molarity of solution}=\frac{0.0151g}{159.6g/mol\times 2.0L}\\\\\text{Molarity of solution}=4.73\times 10^{-5}M$

The chemical equation for the ionization of copper (II) sulfate follows:

$CuSO_4\rightarrow Cu^{2+}+SO_4^{2-}$

1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions

Molarity of copper (II) ions = $4.73\times 10^{-5}M$

Hence, the molar concentration of $Cu^{2+}$ ions in the given amount of sample is $4.73\times 10^{-5}M$

4 0

3 years ago

1. According to the equation, what mass of hydrogen fluoride is necessary to produce 2.3 g of sodium fluoride?

Vanyuwa [196]

Answer:

1.096g

Explanation:

You must know the atomic mass of Hydrogen, Fluorine, and Sodium before you can start:

Hydrogen: 1.008g/mol

Fluorine: 18.99g/mol

Sodium: 22.98g/mol

Next, find the composition percentage of NaF

22.98 + 18.99 = 41.97

Fluorine is 18.99/41.97 =45.25%

Sodium is 100-45.25 = 54.75%

Ultimately we want to know about HF so find how much F is in 2.3g: 2.3 * 0.4525 = 1.041g

Find comp. percentage of HF

18.99+1.008 = 19.998; H/total F/total

Hydrogen 5.041%

Fluorine 94.959%

Laws of conservation of say we have 1.041g of fluorine in our HF. We know 1.041 is 94.959% of the mass of HF so do some simple math to find the remaining: 1.041/0.94959 = 1.096g

4 0

2 years ago

How is sodium extracted from is ore?

Aloiza [94]

Answer:

Sodium is extracted from it's ore by electrolysis of fused sodium chloride.

Explanation:

he process is usually carried out ia a special electrochemical cell called the downs cell. While molten sodium metal is collected at the cathode and also sent to tanks for cooling and storage.

5 0

3 years ago

Why aluminium foils are use to wrap food items

nekit [7.7K]

Because they insulate either the heat or the coolness within the food item. But keep in mind- when it comes to electricity aluminum isn’t an insulator.

3 0

3 years ago

Read 2 more answers

Consider the following reaction at equilibrium: 2 NH3(g) ⇄ N2(g) + 3 H2(g) What does Le Chatelier's principle predict will happe

BabaBlast [244]

Answer : The equilibrium will shift in the left direction.

Explanation :

Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

The given reaction is:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

As per question, when we are adding $N_2$ then the concentration of $N_2$ is increased on product side then the equilibrium will shift in the direction where decrease of concentration of $N_2$ takes place. Therefore, the equilibrium will shift in the left direction.

Thus, the equilibrium will shift in the left direction.

7 0

3 years ago